Question

我有以下PHP代码。当我运行它时，我收到错误' *解析错误：语法错误，第20行/home/ashb/public_html/databaseconnect.php中的意外T_STRING'。*

当代码正常工作时，第20行是：$xml_output .= "<?xml-stylesheet href=\"$xslt_file\" type=\"text/xsl\" ?>";

我需要将代码更改为$xml_output .= "<?xml-stylesheet href=\"$xslt_file\" type=\"text/css\" ?>";。在更改之后发生错误。

它出了什么问题？完整代码包含在下面。

注意： $ xslt_file变量已针对上面的不同代码行进行了适当更改。

<?php 

header("Content-type: text/xml"); 

$host = "###"; 
$user = "###"; 
$pass = "###"; 
$database = "###"; 
$xslt_file = "/xmlstyle.css"; 
$linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host."); 
mysql_select_db($database, $linkID) or die("Could not find database."); 

$query = "SELECT * FROM users WHERE Username = 'Username4';";


$resultID = mysql_query($query, $linkID) or die("Data not found."); 

$xml_output = "<?xml version=\"1.0\"?>\n"; 
//$xml_output .= "<?xml-stylesheet href=\"$xslt_file\" type=\"text/xsl\" ?>";
$xml_output .= "<?xml-stylesheet href=\"$xslt_file\" type=\"text/css\" ?>";

$xml_output .= "<Users>\n"; 

for($x = 0 ; $x < mysql_num_rows($resultID) ; $x++){ 
    $row = mysql_fetch_assoc($resultID); 
    $xml_output .= "\t<Person>\n"; 
    $xml_output .= "\t\t<Username>" . $row['username'] . "</Username>\n"; 
    $xml_output .= "\t\t<Firstname>" . $row['firstname'] . "</Firstname>\n"; 
    $xml_output .= "\t\t<Lastname>" . $row['lastname'] . "</Lastname>\n";
    $xml_output .= "\t\t<Title>" . $row['Title'] . "</Title>\n";
    $xml_output .= "\t\t<Description>" . $row['Description'] . "</Description>\n";  
    $xml_output .= "\t\t<Location>" . $row['Location'] . "</Location>\n";
    $xml_output .= "\t\t<Feeling>" . $row['Feeling'] . "</Feeling>\n";
        // Escaping illegal characters 
        $row['text'] = str_replace("&", "&", $row['text']); 
        $row['text'] = str_replace("<", "<", $row['text']); 
        $row['text'] = str_replace(">", "&gt;", $row['text']); 
        $row['text'] = str_replace("\"", "&quot;", $row['text']); 

    $xml_output .= "\t</Person>\n"; 
} 

$xml_output .= "</Users>"; 

echo $xml_output; 

?>

Answer 1

对抛出错误的线上方的线进行解析会发现香蕉。

//$xml_output .= "<?xml-stylesheet href=\"$xslt_file\" type=\"text/xsl\" ?>";

评论没有评论最终？＆gt;“;

使用像phpstorm / netbeans / zend / etc这样的IDE可以立即显示它。

代码中意外的T-STRING？

1 个答案: