该应用程序的一些背景知识。这是我的WASP和SMPP发射机账户。
我有一个列表<>包含一个对象,该对象具有SMPP PDU的所有必需对象并发送消息。 此列表包含一个名为“路由标签”的属性,路由标签将指示将哪个服务提供商提交到(Vodacom,MTN,Cell C)。
我有另一个帐户列表,我可以绑定到SMPP服务器并发送消息。此列表还包含路由标签,并具有发送器帐户的名称。所以例如Vodacom的路由标签是“D082”,我有两个帐户可以同时绑定。
我现在需要拿第一个List<>并更新字段。让我们说第一个List<>有1000件商品。我需要在第二个List<>中出现的每个“路由标签”的所有帐户中(或多或少均匀地)拆分这些(或多或少均匀)。提及。
我更希望使用linq或lambda来实现所需的功能。
已编辑:添加了代码示例,以便您善意的人可以帮助我:-)抱歉标准不佳,但我很快为您排除了一些代码。我希望这有助于解决我的问题。
static void Main(string[] args)
{
List<MobileAccounts> TransmitterAccounts = new List<MobileAccounts>();//This list contains my transmitter accounts
MobileAccounts item = new MobileAccounts();
item.FriendlyName = "Vodacom 1";
item.RoutingLabel = "D082";
TransmitterAccounts.Add(item);
MobileAccounts item1 = new MobileAccounts();
item1.FriendlyName = "Vodacom 2";
item1.RoutingLabel = "D082";
TransmitterAccounts.Add(item1);
MobileAccounts item2 = new MobileAccounts();
item2.FriendlyName = "MTN 1";
item2.RoutingLabel = "D083";
TransmitterAccounts.Add(item2);
MobileAccounts item3 = new MobileAccounts();
item3.FriendlyName = "MTN 2";
item3.RoutingLabel = "D083";
TransmitterAccounts.Add(item3);
MobileAccounts item4 = new MobileAccounts();
item4.FriendlyName = "MTN 3";
item4.RoutingLabel = "D083";
TransmitterAccounts.Add(item4);
MobileAccounts item5 = new MobileAccounts();
item5.FriendlyName = "CellC 1";
item5.RoutingLabel = "D084";
TransmitterAccounts.Add(item5);
MobileAccounts item6 = new MobileAccounts();
item6.FriendlyName = "CellC 2";
item6.RoutingLabel = "D084";
TransmitterAccounts.Add(item6);
List<SubmitSm> col = new List<SubmitSm>();//this list contains messages in a queue ready for sending
SubmitSm sitem = new SubmitSm();
sitem.DestAddr = "0722222222";//Vodacom number
sitem.RoutingLabel = "D082";
col.Add(sitem);
SubmitSm sitem1 = new SubmitSm();
sitem1.DestAddr = "0722222220";//Vodacom number
sitem1.RoutingLabel = "D082";
col.Add(sitem1);
SubmitSm sitem2 = new SubmitSm();
sitem2.DestAddr = "0722221212";//Vodacom number
sitem2.RoutingLabel = "D082";
col.Add(sitem2);
SubmitSm sitem3 = new SubmitSm();
sitem3.DestAddr = "0830000000";//MTN number
sitem3.RoutingLabel = "D083";
col.Add(sitem3);
SubmitSm sitem4 = new SubmitSm();
sitem4.DestAddr = "0833746005";//MTN number
sitem4.RoutingLabel = "D083";
col.Add(sitem4);
SubmitSm sitem5 = new SubmitSm();
sitem5.DestAddr = "0749999998";//CellC number
sitem5.RoutingLabel = "D084";
col.Add(sitem5);
/*
* Now this is where I will need
* to split all the messages in "col"
* amongst all the transmitter accounts
* I have.
*/
}
public class MobileAccounts
{
/*Please note not all items
are in this class. I have
* removed some as they are not
* neccessary for this demo code.
*/
//[DataMember]
public string FriendlyName;
//[DataMember]
public string BindName;
//[DataMember]
public string BindPassword;
//[DataMember]
public string BindHost;
//[DataMember]
public string BindPort;
//[DataMember]
public string BindType;
//[DataMember]
public string ProviderCode;
//[DataMember]
public string RoutingLabel;
}
public class SubmitSm
{
/*Please note not all items
are in this class. I have
* removed some as they are not
* neccessary for this demo code.
*/
public byte DefaultMessageId { get; set; }
public string DestAddr { get; set; }
public byte DestAddrNpi { get; set; }
public byte DestAddrTon { get; set; }
public string MessageText { get; set; }
public byte PriorityFlag { get; set; }
public byte ProtocolId { get; set; }
public byte RegisteredDelivery { get; set; }
public string ScheduleDeliveryTime { get; set; }
public string ServiceType { get; set; }
public string SourceAddr { get; set; }
public byte SourceAddrNpi { get; set; }
public byte SourceAddrTon { get; set; }
public string ValidityPeriod { get; set; }
public string RoutingLabel { get; set; }
}
感谢所有贡献者。 @NinjaNye你的解决方案很接近,但并不完全符合我的要求。我很感激你的努力。
我想我差不多了,但我很挣扎。有人,有人请帮我弄清楚如下所示的子选择:
List<IGrouping<string, MobileAccounts>> sad1 = TransmitterAccounts.GroupBy(y => y.RoutingLabel).ToList();
col = (List<SubmitSm>)col.Select
(x =>
{
x.ServiceType = sad1.Where
(z =>
z.Key== x.ServiceType
)
.Select
(y =>
new
{
//this should return the Transmitter account that has the lowest count
TransmitterAccount = y.OrderBy(ui => x.ServiceType.Count()).Select(ui => ui.FriendlyName).First()
}
).First().TransmitterAccount;
return x;
}
).ToList();
答案 0 :(得分:2)
我在这里可以看到Linq的唯一用途是使用.Skip()
和.Take()
但是我已经创建了一个扩展方法来整理一些东西。这意味着您可以简单地编写以下内容来拆分任何IEnumerable
。
// In your example above you need to replace `items` with your `col` variable
var result = items.Split(transmitter.Count());
扩展方法
http://www.ninjanye.co.uk/2013/07/splitting-distributing-list-objects.html
public static class EnumerableExtensions
{
public static IEnumerable<IEnumerable<T>> Split<T>(this IEnumerable<T> source, int groups)
{
var listedSource = source.ToList();
int extra;
int groupSize = Math.DivRem(listedSource.Count(), groups, out extra);
while (listedSource.Any())
{
int newSize = groupSize;
if (extra > 0)
{
newSize++;
extra--;
}
yield return listedSource.Take(newSize);
listedSource = listedSource.Skip(newSize).ToList();
}
}
}
结果
我将其设置为快速命令程序以进行测试
以下是一些结果,因此您可以看到项目的拆分方式:
首发帖子(现已重构)
这样的事情应该这样做......但是我简化了例子
// This is your transmitter count
int groups = 4;
// These are your SMS's
List<int> values = new List<int>(){1,2,3,4,5,6,7,8,9};
//Calculate group size
int extra;
int groupSize = Math.DivRem(values.Count, groups, out extra);
var result = new List<IEnumerable<int>>();
while (values.Any())
{
int newSize = groupSize;
if (extra > 0)
{
// Account for extras
newSize++;
extra--;
}
result.Add(values.Take(newSize));
values = values.Skip(newSize).ToList();
}
return result;
答案 1 :(得分:-1)
你应该避免LINQ有副作用。但是你可以像这样在列表中附加对象。
List<MobileAccounts> mas = new List<MobileAccounts>();
List<SubmitSm> sms = new List<SubmitSm>();
var result = mas.Select(ma => new {Sm=(sms.First(sm => sm.RoutingLabel == ma.RoutingLabel)),Ma=ma});
foreach (var r in result)
{
//update Properties here
}