Question

该应用程序的一些背景知识。这是我的WASP和SMPP发射机账户。

我有一个列表＆lt;＆gt;包含一个对象，该对象具有SMPP PDU的所有必需对象并发送消息。此列表包含一个名为“路由标签”的属性，路由标签将指示将哪个服务提供商提交到（Vodacom，MTN，Cell C）。

我有另一个帐户列表，我可以绑定到SMPP服务器并发送消息。此列表还包含路由标签，并具有发送器帐户的名称。所以例如Vodacom的路由标签是“D082”，我有两个帐户可以同时绑定。

我现在需要拿第一个List＆lt;＆gt;并更新字段。让我们说第一个List＆lt;＆gt;有1000件商品。我需要在第二个List＆lt;＆gt;中出现的每个“路由标签”的所有帐户中（或多或少均匀地）拆分这些（或多或少均匀）。提及。

我更希望使用linq或lambda来实现所需的功能。

已编辑：添加了代码示例，以便您善意的人可以帮助我:-)抱歉标准不佳，但我很快为您排除了一些代码。我希望这有助于解决我的问题。

static void Main(string[] args)
    {


        List<MobileAccounts> TransmitterAccounts = new List<MobileAccounts>();//This list contains my transmitter accounts


        MobileAccounts item = new MobileAccounts();
        item.FriendlyName = "Vodacom 1";
        item.RoutingLabel = "D082";
        TransmitterAccounts.Add(item);

        MobileAccounts item1 = new MobileAccounts();
        item1.FriendlyName = "Vodacom 2";
        item1.RoutingLabel = "D082";
        TransmitterAccounts.Add(item1);


        MobileAccounts item2 = new MobileAccounts();
        item2.FriendlyName = "MTN 1";
        item2.RoutingLabel = "D083";
        TransmitterAccounts.Add(item2);


        MobileAccounts item3 = new MobileAccounts();
        item3.FriendlyName = "MTN 2";
        item3.RoutingLabel = "D083";
        TransmitterAccounts.Add(item3);

        MobileAccounts item4 = new MobileAccounts();
        item4.FriendlyName = "MTN 3";
        item4.RoutingLabel = "D083";
        TransmitterAccounts.Add(item4);

        MobileAccounts item5 = new MobileAccounts();
        item5.FriendlyName = "CellC 1";
        item5.RoutingLabel = "D084";
        TransmitterAccounts.Add(item5);

        MobileAccounts item6 = new MobileAccounts();
        item6.FriendlyName = "CellC 2";
        item6.RoutingLabel = "D084";
        TransmitterAccounts.Add(item6);


        List<SubmitSm> col = new List<SubmitSm>();//this list contains messages in a queue ready for sending

        SubmitSm sitem = new SubmitSm();
        sitem.DestAddr = "0722222222";//Vodacom number
        sitem.RoutingLabel = "D082";
        col.Add(sitem);

        SubmitSm sitem1 = new SubmitSm();
        sitem1.DestAddr = "0722222220";//Vodacom number
        sitem1.RoutingLabel = "D082";
        col.Add(sitem1);

        SubmitSm sitem2 = new SubmitSm();
        sitem2.DestAddr = "0722221212";//Vodacom number
        sitem2.RoutingLabel = "D082";
        col.Add(sitem2);

        SubmitSm sitem3 = new SubmitSm();
        sitem3.DestAddr = "0830000000";//MTN number
        sitem3.RoutingLabel = "D083";
        col.Add(sitem3);


        SubmitSm sitem4 = new SubmitSm();
        sitem4.DestAddr = "0833746005";//MTN number
        sitem4.RoutingLabel = "D083";
        col.Add(sitem4);

        SubmitSm sitem5 = new SubmitSm();
        sitem5.DestAddr = "0749999998";//CellC number
        sitem5.RoutingLabel = "D084";
        col.Add(sitem5);

        /*
         * Now this is where I will need
         * to split all the messages in "col"
         * amongst all the transmitter accounts
         * I have. 
         */


    }

public class MobileAccounts
{
    /*Please note not all items 
    are in this class. I have
    * removed some as they are not
    * neccessary for this demo code.               
    */

    //[DataMember]
    public string FriendlyName;

    //[DataMember]
    public string BindName;

    //[DataMember]
    public string BindPassword;

    //[DataMember]
    public string BindHost;

    //[DataMember]
    public string BindPort;

    //[DataMember]
    public string BindType;

    //[DataMember]
    public string ProviderCode;

    //[DataMember]
    public string RoutingLabel;


}

public class SubmitSm
{
   /*Please note not all items 
    are in this class. I have
    * removed some as they are not
    * neccessary for this demo code.               
    */
    public byte DefaultMessageId { get; set; }

    public string DestAddr { get; set; }

    public byte DestAddrNpi { get; set; }

    public byte DestAddrTon { get; set; }

    public string MessageText { get; set; }        

    public byte PriorityFlag { get; set; }

    public byte ProtocolId { get; set; }

    public byte RegisteredDelivery { get; set; }                

    public string ScheduleDeliveryTime { get; set; }

    public string ServiceType { get; set; }

    public string SourceAddr { get; set; }

    public byte SourceAddrNpi { get; set; }

    public byte SourceAddrTon { get; set; }

    public string ValidityPeriod { get; set; }

    public string RoutingLabel { get; set; }

}

感谢所有贡献者。 @NinjaNye你的解决方案很接近，但并不完全符合我的要求。我很感激你的努力。

我想我差不多了，但我很挣扎。有人，有人请帮我弄清楚如下所示的子选择：

List<IGrouping<string, MobileAccounts>> sad1 = TransmitterAccounts.GroupBy(y => y.RoutingLabel).ToList();
col = (List<SubmitSm>)col.Select
                                (x =>
                                    {
                                         x.ServiceType = sad1.Where
                                                               (z =>
                                                                   z.Key==     x.ServiceType
                                                                        )                                                    
                                                                        .Select
                                                                            (y =>
                                                                                    new
                                                                                    {
                                                                                        //this should return the Transmitter account that has the lowest count

                                                                                        TransmitterAccount = y.OrderBy(ui => x.ServiceType.Count()).Select(ui => ui.FriendlyName).First()
                                                                                    }
                                                                            ).First().TransmitterAccount;                                                  

                                              return x;
                                      }
                                    ).ToList();

Answer 1

我在这里可以看到Linq的唯一用途是使用.Skip()和.Take()但是我已经创建了一个扩展方法来整理一些东西。这意味着您可以简单地编写以下内容来拆分任何IEnumerable。

// In your example above you need to replace `items` with your `col` variable
var result = items.Split(transmitter.Count());

扩展方法

~~http://www.ninjanye.co.uk/2013/07/splitting-distributing-list-objects.html~~

http://jnye.co/Posts/10/evenly-splitting-distributing-a-list-of-objects-using-linq-and-extension-methods

public static class EnumerableExtensions
{
    public static IEnumerable<IEnumerable<T>> Split<T>(this IEnumerable<T> source, int groups)
    {
        var listedSource = source.ToList();
        int extra;
        int groupSize = Math.DivRem(listedSource.Count(), groups, out extra);

        while (listedSource.Any())
        {
            int newSize = groupSize;
            if (extra > 0)
            {
                newSize++;
                extra--;
            }
            yield return listedSource.Take(newSize);
            listedSource = listedSource.Skip(newSize).ToList();
        }
    }
}

结果

我将其设置为快速命令程序以进行测试

以下是一些结果，因此您可以看到项目的拆分方式： Example output of splitting

首发帖子（现已重构）

~~这样的事情应该这样做......但是我简化了例子~~

// This is your transmitter count int groups = 4; // These are your SMS's List<int> values = new List<int>(){1,2,3,4,5,6,7,8,9}; //Calculate group size int extra; int groupSize = Math.DivRem(values.Count, groups, out extra); var result = new List<IEnumerable<int>>(); while (values.Any()) { int newSize = groupSize; if (extra > 0) { // Account for extras newSize++; extra--; } result.Add(values.Take(newSize)); values = values.Skip(newSize).ToList(); } return result;

Answer 2

你应该避免LINQ有副作用。但是你可以像这样在列表中附加对象。

        List<MobileAccounts> mas = new List<MobileAccounts>();
        List<SubmitSm> sms = new List<SubmitSm>();

        var result = mas.Select(ma => new {Sm=(sms.First(sm => sm.RoutingLabel == ma.RoutingLabel)),Ma=ma});
        foreach (var r in result)
        {
            //update Properties here
        }

LINQ / Lambda更新通过将项目拆分为偶数组来列出项目

2 个答案: