我有这个数据的表格
id,archive id,ean,index,date,(...)
我有一些项目具有相同的存档ID,相同的ean,但索引不同。
所以在这种情况下,我想删除较旧的(基于日期)项,因此对于每个组合archive_id / index,结果将不会超过1个结果。
答案 0 :(得分:2)
以下(未经测试)应该有效:
DELETE FROM someTable WHERE EXISTS ( SELECT id FROM someTable AS subqTable WHERE
subqTable.id = someTable.id
AND subqTable.ean = someTable.ean
-- and other equality comparisons
AND subqTable.date AFTER someTable.date)
答案 1 :(得分:0)
DELETE duplicates.*
FROM _table
JOIN _table AS duplicates
ON (_table.archive_id = duplicates.archive_id AND _table.index = duplicates.index)
WHERE duplicates.date < _table.date;
答案 2 :(得分:0)
delete t1
from your_table t1
left join
(
select archive_id, ean, min(date) as mdate
from your_table
group by archive_id, ean
) t2 on t1.archive_id = t2.archive_id
and t1.ean = t2.ean
and t1.date = t2.mdate
where t2.mdate is null