我需要更改在同一行按周期显示用户数(ScheduleID)的视图。现在,Period表内容可以增长并包含3个以上的句点。
实际的SQL是:
SELECT r.Code,
SUM(CASE WHEN s.PeriodID=1 THEN 1 ELSE 0 END) AS PeriodID1,
SUM(CASE WHEN s.PeriodID=2 THEN 1 ELSE 0 END) AS PeriodID2,
SUM(CASE WHEN s.PeriodID=3 THEN 1 ELSE 0 END) AS PeriodID3,
SUM(CASE WHEN s.PeriodID IN (1,2,3) THEN 1 ELSE 0 END) AS Total
FROM Schedules s
JOIN Periods p ON p.PeriodID = s.PeriodID
JOIN Resources r ON r.ResourceID = s.ResourceID
GROUP BY r.Code;
示例数据: 表格表
ScheduleID(int) ResourceID(int) ResourceCode(varchar 4) PeriodID(int)
1 1 AA 1
2 1 AA 3
3 1 AA 3
4 2 BB 1
5 3 CC 1
6 1 AA 1
7 3 CC 2
8 3 CC 3
9 2 BB 1
10 2 BB 2
11 2 BB 3
12 1 AA 3
表期间
PeriodID(int) Code (varchar 4)
1 P1
2 P2
3 P3
4 P4
5 P5
6 P6
7 P7
8 P8
我需要的结果是:
ResourceCode PeriodID1 PeriodID2 PeriodID3 ... PeriodID8 TOTAL
AA 2 0 3 0 5
BB 2 1 1 0 4
CC 1 1 1 0 3
“期间”表格内容现在是动态的。
数据库版本是Microsoft SQL 2008
我想知道是否可以在没有创建存储过程的情况下执行此操作...并在一个查询中执行此操作:
SELECT *
FROM (
SELECT R.Code, P.PeriodID, COUNT(S.ScheduleID) AS RPCount
FROM Schedules S INNER JOIN Periods P ON S.PeriodID = P.PeriodID
JOIN Resources R ON S.ResourceID = R.ResourceID
WHERE S.ResourceID is not null
GROUP BY R.Code, P.PeriodID
) as data
PIVOT
(
SUM(RPCount)
--FOR PeriodID IN ([1],[2],[3])
FOR PeriodID IN (SELECT PeriodID From Periods)
)AS pvt
ORDER BY Code
答案 0 :(得分:4)
由于您使用的是SQL Server,因此可以实现PIVOT功能,如果您有未知数量的句点值,则需要使用动态SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME('PeriodId'+cast(periodid as varchar(10)))
from Periods
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT resourcecode, ' + @cols + ' , Total
from
(
select s.resourcecode,
''PeriodId''+cast(p.periodid as varchar(10)) period,
count(*) over(partition by s.resourcecode) Total
from periods p
left join schedules s
on p.periodid = s.periodid
) x
pivot
(
count(period)
for period in (' + @cols + ')
) p
where resourcecode is not null
order by resourcecode'
execute(@query)
见SQL Fiddle with Demo。这给出了一个结果:
| RESOURCECODE | PERIODID1 | PERIODID2 | PERIODID3 | PERIODID4 | PERIODID5 | PERIODID6 | PERIODID7 | PERIODID8 | TOTAL |
------------------------------------------------------------------------------------------------------------------------
| AA | 2 | 0 | 3 | 0 | 0 | 0 | 0 | 0 | 5 |
| BB | 2 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 4 |
| CC | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 3 |
根据您之前使用MySQL标记的问题,我假设您使用MySQL作为数据库。如果是这样,那么你没有PIVOT函数,因此你必须使用带有CASE表达式的聚合函数将数据行转换为列。
如果您的列值已知,则可以对查询进行硬编码:
select resourcecode,
sum(case when period = 'PeriodId1' then 1 else 0 end) PeriodId1,
sum(case when period = 'PeriodId2' then 1 else 0 end) PeriodId2,
sum(case when period = 'PeriodId3' then 1 else 0 end) PeriodId3,
sum(case when period = 'PeriodId4' then 1 else 0 end) PeriodId4,
sum(case when period = 'PeriodId5' then 1 else 0 end) PeriodId5,
sum(case when period = 'PeriodId6' then 1 else 0 end) PeriodId6,
sum(case when period = 'PeriodId7' then 1 else 0 end) PeriodId7,
sum(case when period = 'PeriodId8' then 1 else 0 end) PeriodId8,
count(*) Total
from
(
select concat('PeriodId', p.periodid) Period,
s.resourcecode
from periods p
left join schedules s
on p.periodid = s.periodid
) d
where resourcecode is not null
group by resourcecode;
见SQL Fiddle with Demo。但是如果值是未知的或动态的,那么您将需要使用预准备语句来生成要执行的sql字符串:
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(CASE WHEN period = ''',
concat('PeriodId', periodid),
''' THEN 1 else 0 END) AS `',
concat('PeriodId', periodid), '`'
)
) INTO @sql
FROM periods;
SET @sql
= CONCAT('SELECT resourcecode, ', @sql, ' , count(*) Total
from
(
select concat(''PeriodId'', p.periodid) Period,
s.resourcecode
from periods p
left join schedules s
on p.periodid = s.periodid
) d
where resourcecode is not null
group by resourcecode');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
答案 1 :(得分:0)
使用PIVOT
试试这个
SELECT *
FROM (
SELECT
S.ResourceCode ,
P.PeriodID AS period,
COUNT(*) AS PCount
FROM Schedules S INNER JOIN Periods P ON S.PeriodID =P.PeriodID
GROUP BY S.ResourceCode ,P.PeriodID
) as s
PIVOT
(
PCount,
FOR [period] IN (SELECT DISTINCT PeriodID From Periods)
)AS pivot
答案 2 :(得分:0)
请尝试下面的MS Sql server代码:
DECLARE @column VARCHAR(MAX), @SumQuery VARCHAR(MAX)
SELECT
@column = COALESCE(@column + '], [', '')+ CAST(PeriodID as nvarchar(10)),
@SumQuery = COALESCE(@SumQuery + ']+[', '')+ CAST(PeriodID as nvarchar(10))
FROM
Periods
GROUP BY PeriodID
EXEC ('select *, ['+@SumQuery+'] as [Total] From
(
select * From Schedules
)up
pivot (count(ScheduleID) for PeriodID in (['+@column+'])) as pvt')