Question

我想比较2 NSMutableArray并将不同的对象转换为第三Array。我怎么能这样做？

Array1可以循环对象。

Array1 = "a", "b","c","d","a","b","c";
Array2 = "a", "b", "c";

然后结果

Array3 = "d";

提前致谢

Answer 1

使用集合进行设置操作：

NSSet *set1 = [NSSet setWithArray:array1];
NSMutableSet *set2 = [NSMutableSet setWithArray:array2];
[set2 minusSet:set1];

Answer 2

你也可以尝试一下。

NSMutableArray *array1 = [[NSMutableArray alloc]initWithObjects:@"1",@"2",@"3",@"1", nil];
NSMutableArray *array2 = [[NSMutableArray alloc]initWithObjects:@"2",@"1", nil];    

NSMutableArray *largeArray;
NSMutableArray *shortArray;
if([array1 count] > [array2 count]){
    largeArray = array1;
    shortArray = array2; 
} else {
    largeArray = array2;
    shortArray = array1; 
}
[largeArray removeObjectsInArray:shortArray];

for (NSString *va in largeArray) {
    NSLog(@"%@",va);
}

Answer 3

NSMutableArray *gotDiffArry= [[NSMutableArray alloc] init];
for(int i = 0 ; i < FirstArray.count; i++) {
    if(i < seconArray.count){
        if(![seconArray[i] isEqual:firstArray[i]]){
             [gotDiffArry addObject:[NSNumber numberWithInt:i]];
         }
    } else {
        [gotDiffArry addObject:[NSNumber numberWithInt:i]];
    }
}

<强>编辑：

for (int i = 0 ; i < firstArray.count ; i ++)
{

 NSString *search = [firstArray objectAtIndex:i];
 NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY SELF CONTAINS %@", search];
 NSMutableArray *temAraay = [secondArray filteredArrayUsingPredicate: predicate];
 if(temArray.count >=0 )
 {
   NSLog("%@", [temArray objectAtIndex:0]); 
 }
}

Answer 4

我使用了以下内容并获得了预期的结果：

for(int i =0; i<[arraytwo count]; i++)
{
    if (![arrayone containsObject:[arraytwo objectAtIndex:i]])
        [arraythree addObject: [arraytwo obectAtIndex:i]];
}    
NSLog(@"%@",arraythree);

比较2 nsmutablearray并在ios中获得不同的对象到第三个数组

4 个答案: