用android与web数据库通信

时间:2013-07-12 08:19:05

标签: php android http-post webservice-client

我在Android应用程序中有一个注册表单,其中包含用户名和密码。我希望当用户单击注册表单的提交按钮时,用户名和密码将保存到Web数据库(mySql数据库)中。

当用户按下提交按钮时,执行sendPostRequest(givenUsername, givenPassword);

和sendPostRequest()函数就是那样

private void sendPostRequest(String givenUsername, String givenPassword) {

    class SendPostReqAsyncTask extends AsyncTask<String, Void, String>{

        @Override
        protected String doInBackground(String... params) {

            String paramUsername = params[0];
            String paramPassword = params[1];

            System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);

            HttpClient httpClient = new DefaultHttpClient();


            HttpPost httpPost = new HttpPost("http://10.0.2.2/imon.php");



            BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
            BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);


            List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
            nameValuePairList.add(usernameBasicNameValuePair);
            nameValuePairList.add(passwordBasicNameValuePAir);

            try {

                UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);

                httpPost.setEntity(urlEncodedFormEntity);

                try {

                    HttpResponse httpResponse = httpClient.execute(httpPost);


                    InputStream inputStream = httpResponse.getEntity().getContent();

                    InputStreamReader inputStreamReader = new InputStreamReader(inputStream);

                    BufferedReader bufferedReader = new BufferedReader(inputStreamReader);

                    StringBuilder stringBuilder = new StringBuilder();

                    String bufferedStrChunk = null;

                    while((bufferedStrChunk = bufferedReader.readLine()) != null){
                        stringBuilder.append(bufferedStrChunk);
                    }

                    return stringBuilder.toString();

                } catch (ClientProtocolException cpe) {
                    System.out.println("First Exception caz of HttpResponese :" + cpe);
                    cpe.printStackTrace();
                } catch (IOException ioe) {
                    System.out.println("Second Exception caz of HttpResponse :" + ioe);
                    ioe.printStackTrace();
                }

            } catch (UnsupportedEncodingException uee) {
                System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
                uee.printStackTrace();
            }

            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);

            if(result.equals("working")){
                Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
            }else{
                Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
            }
        }           
    }

    SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
    sendPostReqAsyncTask.execute(givenUsername, givenPassword);     
}

我的imon.php是这样的:

 <?php

 $varUsername = $_POST['paramUsername'];
 $varPassword = $_POST['paramPassword'];

 if($varUsername != "" && $varPassword != ""){

$con = mysql_connect('localhost', 'root', '');
 if (!$con) {
die('Not connected : ' . mysql_error());
 }

  // make foo the current db
  $db_selected = mysql_select_db('post_db', $con);
  if (!$db_selected) {
   die ('Can\'t use foo : ' . mysql_error());
  }

  $sql="INSERT INTO post_table (username,password)
 VALUES
  ('$varUsername ','$varPassword')";

   if (!mysql_query($con,$sql))
    {
    die('Error: ' . mysql_error($con));
     }

echo 'working';
  }else
       {
   echo 'invalid';
       }
   ?>

但数据未插入my-sql数据库。

我错在哪里? 如何将注册表单的数据插入到Web数据库中?

1 个答案:

答案 0 :(得分:0)

你不能这样做

mysql_connect('localhost', 'root', '');

然后执行此操作

if (!mysqli_query($con,$sql))

mysql和mysqli是单独的扩展。你无法与他人分享资源。

mysqli_query()和mysql_query()不采用相同的参数顺序。 mysql_query()的第一个参数是查询。 mysqli_query中的第一个参数是连接资源。您之前也在混合连接。