Question

我想在结果中按id显示不同的记录，但它不起作用。我使用了以下查询，

SELECT distinct(b.`id`), b.`from_name`, b.`posted_on`, b.`subject`, a.`to` FROM `message` as b, `message_recepient` as a WHERE b.`id` in (15063,15106,15075,15170) AND b.`id` = a.`msg_id`

按查询返回的数据是

15063   John Doe    2013-03-18 07:18:15     hello       59640
15075   Dan Patrik  2013-04-09 06:27:04     hiiiiii     59640
15106   Rahul Y     2013-04-17 13:35:27     good morning    50452
15106   Rahul Y     2013-04-17 13:35:27     good morning    55129
15106   Rahul Y     2013-04-17 13:35:27     good morning    59610
15106   Rahul Y     2013-04-17 13:35:27     good morning    59622
15106   Rahul Y     2013-04-17 13:35:27     good morning    59640
15170   Ritesh D    2013-04-24 05:02:56     hi      59640

Answer 1

尝试加入

SELECT distinct(b.`id`),b.`from_name`,b.`posted_on`,b.`subject`, a.`to` FROM `message` as b inner join `message_recepient` as a  on (b.`id` = a.`msg_id`) WHERE b.`id` in (15063,15106,15075,15170)

或，

SELECT b.`id`,b.`from_name`,b.`posted_on`,b.`subject`, a.`to` FROM `message` as b inner join `message_recepient` as a  on (b.`id` = a.`msg_id`) WHERE b.`id` in (15063,15106,15075,15170) group by id

无法从mysql查询中获得明显的结果？

1 个答案: