Question

如何将post变量传递给segment url？我可以从网址读取它，但我无法设置它... 我到目前为止：路由上的$route['shop/find/(:any)']= "shop/find/$1";，视图上的find.php和我的函数`

function find()
    {
            $this->load->model('shopFront/find');
            $this->load->model('currency');
            $this->load->model('shopFront/calculate');
            $this->load->model('shop/proccess');
            $data = $this->commondatashop->general();
            $inputSlug = $this->input->post('findSlug');
            $data['tofind'] = $inputSlug;
            $data['cartInfo'] = $this->shopcart;
            $data['Currency'] = $this->currency;
            $data['Calculate'] = $this->calculate;
            $data['Proccess'] = $this->proccess;
            $data['title'] = "1.4.U Shop | Find";
            $finder = $this->find;
            $data['finderservice'] = $finder;
            $data['user_id'] = $this->session->userdata('user_id');
            $data['user_name'] = $this->session->userdata('user_name');
            $this->load->view('shop/top/topNew',$data);
            $this->load->view('shop/content/find',$data);

            //footer
            $curravailable = $this->calculate->getCurrencies();
            if ( $curravailable !== false )
            {
                $data['currencies'] = $curravailable;
            }
            else
            {
                $data['currencies'] = 'none';
            }
            $this->load->view('shop/footer',$data);


    }`

如何使用url段将变量发布到find（）函数？

Answer 1

您需要找到接受默认

的参数

function find($i=0) {
  //$i is whatever is in the URL or defaults to 0

Answer 2

在您看来：

echo form_open('/shop/find');
echo form_input('findSlug','');
echo form_submit('submit', 'Submit');
echo form_close();

控制器：

$data[slug] = $this->input->post('findSlug');

您还需要加载表单助手

将post变量传递给url

2 个答案: