Question

我正在实现推送通知，如果应用程序位于前台，则会正确接收它们，并使用数据调用didReceiveRemoteNotification。所以我认为令牌和服务器问题都是零。当应用程序处于后台时它变得很丑陋：我发送通知并且从未在通知中心显示为收到，而不是显示徽章。在设置/通知/ MyApp中，一切都处于活动状态。也许是因为我正在使用开发证书或因为Apple的沙盒问题？任何想法将不胜感激。谢谢

Answer 1

固定。在创建有效负载时，我使用的是简单数组，而不是带有['aps']键的数组。服务器端问题。我不知道为什么Apple会在文档说它不会发送通知时发送不好的信息。这个细节让我觉得服务器端还可以，这就是为什么我没有粘贴代码，对不起。

<强>错误：

  $payload = array('alert' => $this->code->getText(),
                   'sound' => 'default', 
                   'badge' => '1');
  $message['payload'] = json_encode($payload);

从右：

$body['aps'] = array( 'alert' => $this->code->getText(), 'sound' => 'default', 'badge' => '1' ); $message['payload'] = json_encode($body);

发送代码......

if ($this->sendNotification($message['device_token'], $message['payload'])) { } else { // failed to deliver $this->reconnectToAPNS(); }

Answer 2

根据您的描述，我假设您某些时候正在接收APN（Apple推送通知）。仔细检查AppDelegate中的代码，看看你是否有以下内容：

在- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions

中你应该

[[UIApplication sharedApplication] registerForRemoteNotificationTypes:(UIRemoteNotificationTypeBadge | UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];

在didReceiveRemoteNotification中尝试此代码，看看收到APN时会发生什么：

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo{
NSLog(@"remote notification: %@",[userInfo description]);
NSDictionary *apsInfo = [userInfo objectForKey:@"aps"];

NSString *alert = [apsInfo objectForKey:@"alert"];
NSLog(@"Received Push Alert: %@", alert);

NSString *sound = [apsInfo objectForKey:@"sound"];
NSLog(@"Received Push Sound: %@", sound);

NSString *badge = [apsInfo objectForKey:@"badge"];
NSLog(@"Received Push Badge: %@", badge);
}

最后确保您实际上已成功注册接收APN：

- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken {
NSLog(@"My token is: %@", deviceToken);
}

包含此代码，以防您在注册APN时出错：

- (void)application:(UIApplication*)application didFailToRegisterForRemoteNotificationsWithError:(NSError*)error {
NSLog(@"Failed to get token, error: %@", error);
}

系统未显示推送通知

2 个答案: