Question

ajax帖子命中服务器并提供正确的信息，但即使它有效，它仍然会遇到错误功能。就绪状态为0，因此它表示它甚至没有发出请求。

            var serviceURL = '/ContactForm/FirstAjax';
            $.ajax({
                type: "POST",
                url: serviceURL,
                data: JSON.stringify(formInfo),
                contentType: "application/json; charset=utf-8",
                dataType: "json",
                success: function () {
                            alert("Worked");
                        },

                error: function (xhRequest, ErrorText, thrownError) {
                    alert("Failed to process correctly, please try again" + "\n xhRequest: " + xhRequest + "\n" + "ErrorText: " + ErrorText + "\n" + "thrownError: " + thrownError);

                }
            });

错误消息为： Error Msg

我的控制器看起来像这样：

    [HttpPost]
    [ActionName("FirstAjax")]
    [OutputCache(NoStore = true, Duration = 0, VaryByParam = "*")]
    public JsonResult FirstAjax(ContactForm contactForm)
    {            
        return Json("works", JsonRequestBehavior.AllowGet);
    }

Answer 1

你的ajax post方法或你的控制器有错误。如果按原样保留ajax方法，则可以将控制器修改为：

[HttpPost]
[ActionName("FirstAjax")]
[OutputCache(NoStore = true, Duration = 0, VaryByParam = "*")]
public JsonResult FirstAjax()
{            
    var postedData = new StreamReader(Request.InputStream);
    var jsonEncoded = postedData.ReadToEnd(); //String with json
    //Decode your json and do work. 
    return Json("works", JsonRequestBehavior.AllowGet);
}

如果您不想更改控制器，则需要将javascript更改为：

var serviceURL = '/ContactForm/FirstAjax';
$.ajax({
        type: "POST",
        url: serviceURL,
        data: { contactForm: JSON.stringify(formInfo) },
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        success: function () {
                     alert("Worked");
                },
        error: function (xhRequest, ErrorText, thrownError) {
            alert("Failed to process correctly, please try again" + "\n xhRequest: " + xhRequest + "\n" + "ErrorText: " + ErrorText + "\n" + "thrownError: " + thrownError);

        }
    });

希望这有帮助。

Answer 2

我正在使用Fiddler并意识到它正在执行GET而不是POST。我想出了如何修复它。当我提交表单时，它使用onsubmit="submitForm();"调用Javascript。通过提交表单，它会在网址上预先形成GET，而不是POST。我修复了onsubmit="submitForm(); return false"。

答案来源 - jQuery: why does $.post does a GET instead of a POST

Ajax Post投掷错误

2 个答案: