从像assets-library这样的URL获取UIImage：/

Question

我正在开发适用于iPad的iOS应用程序，我正在使用名为Grabkit的存储库，以获取来自Instagram和Flicker等不同服务的图像以及来自相机胶卷的图像。问题是，当用户从滚动中选择一张图片时我得到的URL和URL如下：assets-library：//asset/asset.JPG？id = DCFB9E49-93AA-49E3-89C8-2EE64AE2C4C6＆amp; ext = JPG 我已经尝试了一些代码来从这种路径中获取图像，但没有人工作过，如下所示：

 ALAssetsLibrary* library = [[ALAssetsLibrary alloc] init];

    // Ask for the "Asset" for the URL. An asset is a representation of an image in the Photo application.
    [library assetForURL:originalImage.URL
             resultBlock:^(ALAsset *asset) {

                 // Here, we have the asset, let's retrieve the image from it

                 CGImageRef imgRef = [[asset defaultRepresentation] fullResolutionImage];
                 /* Instead of the full res image, you can ask for an image that fits the screen
                  CGImageRef imgRef  = [[asset defaultRepresentation] fullScreenImage];
                  */

                 // From the CGImage, let's build an UIImage
               imatgetemporal = [UIImage imageWithCGImage:imgRef];


             } failureBlock:^(NSError *error) {

                 // Something wrong happened.

             }];

我的代码中的某些内容是错误的吗？我必须尝试其他代码吗？