Question

我有一个数据结构列表：

        public List<Personal> Personals()
        {
            return new List<Personal>
                {
                    new Personal
                        {
                            Id = 0,
                            Name = "Name 0"
                        },
                    new Personal
                        {
                            Id = 1,
                            Name = "Name 1",
                            ParentId = 0
                        },
                    new Personal
                        {
                            Id = 2,
                            Name = "Name 2",
                            ParentId = 0
                        },
                    new Personal
                        {
                            Id = 3,
                            Name = "Name 3",
                            ParentId = 0
                        },
                    new Personal
                        {
                            Id = 4,
                            Name = "Name 4",
                            ParentId = 1
                        },
                    new Personal
                        {
                            Id = 5,
                            Name = "Name 5",
                            ParentId = 1
                        },
                    new Personal
                        {
                            Id = 6,
                            Name = "Name 6",
                            ParentId = 2
                        },
                    new Personal
                        {
                            Id = 7,
                            Name = "Name 7",
                            ParentId = 2
                        },
                    new Personal
                        {
                            Id = 8,
                            Name = "Name 8",
                            ParentId = 4
                        },
                    new Personal
                        {
                            Id = 9,
                            Name = "Name 9",
                            ParentId = 4
                        },
                };
        }

我想建一棵树：

public List<Tree> Trees()
            {
                return new List<Tree>
                    {
                        new Tree
                            {
                                Id = 0,
                                Name = "Name 0",
                                List = new List<Tree>
                                    {
                                        new Tree
                                            {
                                                Id = 1,
                                                Name = "Name 1",
                                                List = new List<Tree>
                                                    {
                                                        new Tree
                                                            {
                                                                Id = 4,
                                                                Name = "Name 4"
                                                            },
                                                        new Tree
                                                            {
                                                                Id = 5,
                                                                Name = "Name 5"
                                                            }
                                                    }
                                            }
                                    }
                            }
                    };
            }

如何使用LinQ构建一个树来对象？我必须使用，但它不能正常工作，见下文：

public List<Tree> GetTree(List<Personal> list)
        {
            var listFormat = list.Select(x => new Tree
                {
                    Id = x.Id,
                    Name = x.Name,
                    ParentId = x.ParentId
                }).ToList();

            var lookup = listFormat.ToLookup(f => f.ParentId);
            foreach (var tree in listFormat)
            {
                tree.List = lookup[tree.Id].ToList();
            }

            return listFormat;
        }

Answer 1

你应该使用递归：

public void SomeMethod() {
     // here you get your `list`
     var tree = GetTree(list, 0);
}

public List<Tree> GetTree(List<Personal> list, int parent) {
    return list.Where(x => x.ParentId == parent).Select(x => new Tree {
        Id = x.Id,
        Name = x.Name,
        List = GetTree(list, x.Id)
   }).ToList();
}

Answer 2

与上面相同，只有此代码检查您的根节点是否具有与其自己的ID匹配的ParentID。

    public void SomeMethod()
    {
        // here you get your `list`
        var tree = GetTree(list, 0);
    }

    public List<Tree> GetTree(List<Personal> list, int parent)
    {
        return list.Where(x => x.ParentId == parent).Select(x => new Tree
        {
            Id = x.Id,
            Name = x.Name,
            List = x.ParentId != x.Id ? GetTree(list, x.Id) : new List<Tree>()
        }).ToList();
    }

如何使用Linq构建层次结构来对象？

2 个答案: