Question

如何对这个json进行排序。下面的json在浏览器中输出。

{
event: {
July: [
{
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
}
],
Aug: [
{
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
}
],
Sept: [ ],
Oct: [ ],
Nov: [ ],
Dec: [
{
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
stamp: "1386019800"
},
{
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
stamp: "1387921620"
}
],
Jan: [ ],
Feb: [ ],
Mar: [ ], 
Apr: [ ],
May: [ ],
June: [ ]
}
}

以下是在获取控制台时。

 Apr =     (
);
Aug =     (
            {

        createdSeatMap: "yes",
        status: "1",
        completed: "1",
        eventPayment: "0",
    }
);
Dec =     (
           {
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
stamp: "1386019800"
},
{
createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
stamp: "1387921620"
}
);
Feb =     (
);
Jan =     (
);
July =     (
            {
        createdSeatMap: "yes",
status: "1",
completed: "1",
eventPayment: "0",
    }
);
June =     (
);
Mar =     (
);
May =     (
);
Nov =     (
);
Oct =     (
);
Sept =     (
);

以下是我正在使用的代码

NSMutableArray *dictAllValues = [[NSMutableArray alloc]init];
NSMutableDictionary *getDataDict = [[NSMutableDictionary alloc]init];

getDataDict = [self.mGetDataDict valueForKey:@"event"];

NSArray *dictAllKeys = [[NSArray alloc] init];

dictAllKeys = [getDataDict allKeys];

NSLog(@"dict :%d", [dictAllKeys count]);
for(int i=0; i<[getDataDict count]; i++)
{
    NSString *strKey = [dictAllKeys objectAtIndex:i];
    [dictAllValues addObjectsFromArray:[getDataDict valueForKey:strKey]];
    if(i==0)
    {

        NSArray *cVals = [dictAllValues valueForKey:strKey];
        int c = [cVals count];
        NSLog(@"values:%@", cVals);
        NSLog(@"values:%@", dictAllValues);
        [self.mArrMOneEvents addObject:[NSString stringWithFormat:@"%d", c]];
        self.mArrMOneEtType = [dictAllValues valueForKey:@"type"];
        self.mArrMOneEtTime = [dictAllValues valueForKey:@"time"];
        self.mArrMOneEtSeatMap = [dictAllValues valueForKey:@"createdSeatMap"];
        self.mArrMOneEtSeatId = [dictAllValues valueForKey:@"seatMapId"];
        self.mArrMOneEtQuant = [dictAllValues valueForKey:@"quantity"];
        self.mArrMOneEvents = [dictAllValues valueForKey:@"eventName"];
        self.mArrMOneETLoc = [dictAllValues valueForKey:@"location"];
        self.mArrMOneEtEId = [dictAllValues valueForKey:@"id"];
        self.mArrMOneEtDesc = [dictAllValues valueForKey:@"description"];
        self.mArrMOneEtDate = [dictAllValues valueForKey:@"date"];
        self.mArrMOneEtCurr = [dictAllValues valueForKey:@"currency"];
        self.mArrMOneEtCost = [dictAllValues valueForKey:@"cost"];
        self.mArrMOneEtCateg = [dictAllValues valueForKey:@"category"];
        self.mArrmOneEtImg = [dictAllValues valueForKey:@"banner"];
        NSLog(@"array one:%d", [self.mArrMOneEvents count]);
    }
}

这是我试过的

NSArray *keys = [[getDataDict allKeys] sortedArrayUsingSelector: @selector(compare:)];

NSMutableArray *array = [NSMutableArray arrayWithCapacity: [keys count]];
for (NSString *key in keys) {
    [array addObject: [getDataDict objectForKey: key]];
}
NSLog(@"array:%@", array);

下面是描述此要求的图像。 enter image description here 需要与来自服务器的方式相同的响应，请在上面指导。提前谢谢。

Answer 1

排序字典键的复杂方法

NSCalendar *calender = [NSCalendar currentCalendar];
NSDateFormatter *dateFormatter = [NSDateFormatter new];
[dateFormatter setDateFormat:@"MMM"];

NSDateComponents *components = [NSDateComponents new];
components.month = 1;

NSMutableArray *months = [@[] mutableCopy];

NSDate *date = [NSDate date];

[months addObject:[dateFormatter stringFromDate:date]];
while ([months count]<12){
    date = [calender dateByAddingComponents:components toDate:date options:0];
    [months addObject:[dateFormatter stringFromDate:date]];
}
//A sample dictionary to test
NSDictionary *dictionary = @{@"Jan": @"",
                             @"Feb": @"",
                             @"Mar": @"",
                             @"Apr": @"",
                             @"May": @"",
                             @"Jun": @"",
                             @"Jul": @"",
                             @"Aug": @"",
                             @"Sep": @"",
                             @"Oct": @"",
                             @"Nov": @"",
                             @"Dec": @""};

NSArray *keys = [[dictionary allKeys] sortedArrayUsingComparator:
                 ^NSComparisonResult(NSString * key1, NSString * key2) {
    NSUInteger index1 = [months indexOfObject:[key1 substringToIndex:3]];
    NSUInteger index2 = [months indexOfObject:[key2 substringToIndex:3]];
    return [@(index1) compare:@(index2)];
}];

NSLog(@"keys : %@",keys);

Answer 2

您遇到的主要问题是您的JSON响应未正确格式化。您的JSON响应中有许多不需要的东西。看看你的JSON响应：

{
event: {
            July: [
                      {
                          createdSeatMap: "yes",
                          status: "1",
                          completed: "1",
                          eventPayment: "0",
                      }
                  ]
       }
}

在您的情况下，event应该是不同月份的事件数组。现在，在每个数组中，您将拥有该月的所有事件。将键（在上面的示例中，“July”）作为值添加到数组，而不是将其作为键。请参阅响应的示例：

{
event: {
            [
                  Month : "July",      <<--- //See this Line.
                  {
                       createdSeatMap: "yes",
                       status: "1",
                       completed: "1",
                       eventPayment: "0",
                  }
             ]
       }
}

当您的服务器返回字典时，您的响应将永远不会维护订单。您应该从服务器端修改您的响应，如上所述。

接收来自服务器的相同JSON响应

2 个答案: