Question

所以我的变量在inputnfo（）中明确定义，为什么我得到一个未定义的错误？尝试＆amp;除了呢？我添加了删除...交换了所有周围，似乎无法找到解决方案，并在线答案似乎非常基于情况...提前感谢：）

Super New＆amp;改进编辑：现在获得UnboundLocalError

import random

alpha = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

strgen = []

retry = 0

### Defining

def inputnfo():
    global much
    much = input('how long do you want your random word/lucky number to be: ')
    global which
    which = raw_input('would you like letters or numbers?(let,num, or mix?):').lower


def generate():
    while much > 0:
        if which == 'let':
            strgen.append(random.choice(alpha))
            much -= 1
            print '.'

        elif which == 'num':
            strgen.append(random.randint(1,9))
            much -= 1
            print '.'

        elif which == 'mix':
            mixer = random.choice([0,1])
            if mixer == 0:
                strgen.append(random.choice(alpha))
                much -= 1
                print '.'

            elif mixer == 1:
                strgen.append(random.randint(1,9))
                much -= 1
                print '.'

def finish():

    finito = ''.join(strgen)
    print 'Generation Completed!\n'

    if which == 'let':
        print 'Your randomly generated string is:' + finito

    elif which == 'num':
        print 'Your randomly generated number is:' + finito

    elif which == 'mix':
        print 'Your randomly generated Alpha-Numerical string is:' + finito

### Running

inputnfo()

while much != 0:
    generate()

finish()

Answer 1

因为函数inputnfo（）中的变量“很多”本身就是该函数的本地变量。这就是为什么你在while循环中得到一个未定义的错误。有两个解决方案 1.通过包含行

使变量“更加”全局

def inputnfo():
    global much
    try:

然后删除generate function

的参数

或者 2.让函数inputnfo（）返回很多并在while循环中使用此返回值并生成函数

为变量“which”做同样的事情并添加一行which = "" befor

which = ""
def inputnfo():
    global much

Python 2.7：在前一个函数中定义的变量，接收未定义的错误

Super New＆amp;改进编辑：现在获得UnboundLocalError

1 个答案: