Python - randint()返回空范围,崩溃错误

时间:2013-07-11 04:19:31

标签: python random crash

我已经能够在我的扑克程序中多次复制此错误,并尝试了各种不成功的解决方案。这是最新的:

Traceback (most recent call last):
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1868, in <module>
    if __name__ == '__main__': main()
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1866, in main
    mainGame = Game(opponent)
  File "C:\Users\Pangloss\Desktop\tgchanpoker\poker.py", line 1443, in __init__
    if randint(1,betCheck+(10-handValue[1]))<5 or gameStage == "bettingStay":
  File "C:\Python27\lib\random.py", line 241, in randint
    return self.randrange(a, b+1)
  File "C:\Python27\lib\random.py", line 217, in randrange
    raise ValueError, "empty range for randrange() (%d,%d, %d)" % (istart, istop, width)
ValueError: empty range for randrange() (1,-7, -8)

以下是相关代码:

                    handValue = checkHand(opponent.cards.cards)
                    if gameStage == "betting" or gameStage == "final" or gameStage == "finalresponding":
                        betCheck = 18-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness
                    elif gameStage == "extendedFinal":
                        betCheck = 16-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness-(pot/100)
                    else:
                        betCheck = 16-handValue[1]-round(betAmount/(setMax/5))+opponent.brashness
                    foldCheck = 16-handValue[1]-round(betAmount/(setMax/3))+opponent.brashness+(pot/100)
                    if randint(1,betCheck+(10-handValue[1]))<5 or gameStage == "bettingStay":

2 个答案:

答案 0 :(得分:0)

检查betCheck+(10-handValue[1])的值。从追溯来看,它是-8。

答案 1 :(得分:0)

此代码

randint(1,betCheck+(10-handValue[1]))

给你这个

randrange(1,-7,-8)

这意味着betCheck+(10-handValue[1])正在给你-8

该范围根本不会给你任何数字,因为betCheck +(10-handValue [1]))是负数而范围无效

你需要检查设置betcheck和handvalue [1]的代码,看看为什么它如此负面