现在,这段代码显示了所有五种冰淇淋口味。我试图只显示有货的味道。
<pre><?php
$flavors = array();
$flavors[] = array("name" => "Cookie Dough", "in_stock" => true);
$flavors[] = array("name" => "Vanilla", "in_stock" => false);
$flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false);
$flavors[] = array("name" => "Bacon Me Crazy", "in_stock" => true);
$flavors[] = array("name" => "Strawberry", "in_stock" => false);
foreach($flavors as $flavor) {
echo $flavor["name"] . "\n";
}
?></pre>
答案 0 :(得分:1)
这应该可以解决问题。
foreach($flavors as $flavor) {
if($flavor['in_stock'] === true)
echo $flavor["name"] . "\n";
}
答案 1 :(得分:0)
您仍然可以使用foreach循环,但使用if
语句
foreach($flavors as $flavor) {
if ($flavor["in_stock"])
echo $flavor["name"] . "\n";
}
答案 2 :(得分:0)
替换
echo $flavor["name"] . "\n";
与
if ($flavor['in_stock']) {
echo $flavor["name"] . "\n";
}
答案 3 :(得分:0)
foreach($flavors as $flavor)
{
if ($flavor['in_stock'])
{
echo $flavor["name"] . "\n";
}
}
答案 4 :(得分:0)
$flavorsInStock = array_filter($flavors, function($flavor) {
return $flavor['in_stock'];
});
会给你一个新阵列,只有库存的味道。