Question

在我正在处理的程序中，我正在读取来自.xls文件的数据，看起来像这样

2012-SEP-27     04:35:00        0.035173        0.019666        0.001566        -0.002356       0.028054  0.009819        -9999.000000    0.036353        0.021943        0.003582        -0.0006520.025411 0.009548        -9999.000000    0.035703        0.019268        0.003582        -0.0005340.040426 0.010700        -9999.000000    56.904729       95.722267       7.827207

将其制成列，对数字进行一些筛选（这包括将某些列组合成“过滤器”），然后尝试将其写回另一个.xls文件。我可以将它写入一个文件，输出文件看起来与输入文件相同，但当我尝试访问单独的列时，我要么不能（它将整个事物视为一列）或者我只能逐个字符地访问它。

我尝试了多种方式格式化输出，包括：

AA = ('{0}     {1}     {2}     {3}     {4}     {5}     {6}     {7}     {8}     {9}     {10}    {11}    {12}    {13}    {14}    {15}    {16}    {17}    {18}    {19}    {20}    {21}    {22}    {23}    {24}    {25}'.format(date, time, filter1[0], filter1[1], filter1[2], filter2[0], filter2[1], filter2[2], filter3[0], filter3[1], filter3[2], filter4[0], filter4[1], filter4[2], filter5[0], filter5[1], filter5[2], filter6[0], filter6[1], filter6[2], filter7[0], filter7[1], filter7[2], LZA, SZA, LAM) + '\n')

AA = [date, time, float(filter1[0]), float(filter1[1]), float(filter1[2]), filter2[0], filter2[1], filter2[2], filter3[0], filter3[1], filter3[2], filter4[0], filter4[1], filter4[2], filter5[0], filter5[1], filter5[2], filter6[0], filter6[1],filter6[2], filter7[0], filter7[1],filter7[2],LZA, SZA, LAM]


AA = [(date, time, filter1[0], filter1[1], filter1[2], filter2[0], filter2[1], filter2[2], filter3[0], filter3[1], filter3[2], filter4[0], filter4[1], filter4[2], filter5[0], filter5[1], filter5[2], filter6[0], filter6[1], filter6[2], filter7[0], filter7[1], filter7[2], LZA, SZA, LAM)]

我正在寻找一些关于将数据写入文件的一般帮助，以便列可以访问它，我正在编写的代码很难简洁地解释，所以一般的例子很好。我是python的新手，非常感谢你的帮助和耐心

修改

                writer = csv.writer(outputfile, delimiter = '\t')
                row = [date, time]
                row.extend(map(float, filter1))
                for filter in (filter2, filter3, filter4, filter5, filter6, filter7):
                        row.extend(filter)
                row.extend([LZA, SZA, LAM])
                writer.writerow(row)

给我一个看起来像

的输出

2012-SEP-27     04:35:00        -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -.0      56.904729       95.722267       "7.827207
"
2012-SEP-27     04:39:00        -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 -9999.0 0.0      -9999.0 56.007862       96.708467       "1.784808
"
2012-SEP-27     04:43:00        0.036885        0.038065        0.047741        0.021099        0.0      0.035384        0.034978        0.045806        0.019952        0.013064        0.021955
"
2012-SEP-27     04:47:00        0.038996        0.039075        0.04026 0.020357        0.012688 .036156 0.033027        0.011406        0.011693        0.011979        -9999.0 -9999.0 -9999.0 5
"
2012-SEP-27     04:51:00        -9999.0 -9999.0 -9999.0 0.019505        0.016133        0.018253 146     0.043547        0.012732        0.014486        0.015731        -9999.0 -9999.0 -9999.0 5
"

我正在尝试使用

访问每个列

from __future__ import division
import csv
v = open("Pt_2_Test_Data.csv", 'wb') 

with open("outputfile.csv", 'rb') as w:
        reader = csv.reader(w, delimiter = '\t', quotechar = '|')

        for row in w:
                columns = row.split(',')
                date = columns[0]
                time = columns[1]

打印日期会给我日期，但是除了[0]之外的任何其他内容都会给出错误

    time = columns[1]
IndexError: list index out of range

Answer 1

使用csv模块并编写标签分隔值：

import csv

with open('outputfile.csv', 'wb') as outputfile:
    writer = csv.writer(outputfile, delimiter='\t')
    row = [date, time]
    row.extend(map(float, filter2))
    for filter in (filter2, filter3, filter4, filter5, filter6, filter7):
        row.extend(filter)
    row.extend([LZA, SZA, LAM])
    writer.writerow(row)

您的输入文件也很可能使用制表符分隔的列，而不是多个空格。

格式化python输出文件，以便以后可以访问列

1 个答案: