我在工作中使用Java应用程序。我需要发送点击按钮并填写文本框。我希望这些行动能够在后台发生。窗口的ahk_class是SunAwtFrame,没有任何控件暴露给WindowSpy。
我使用JavaFerret来确定我要按的第一个按钮是否有AccessibleAction
Version Information:
Java virtual machine version: 1.7.0_25
Access Bridge Java class version: 1.7.0_25
Access Bridge Java DLL version: AccessBridge 2.0.2
Access Bridge Windows DLL version: AccessBridge 2.0.2
AccessibleContext information:
Name: New Call
Description: Place a new call
Role: push button
Role in en_US locale: push button
States: enabled,focusable,visible,showing,opaque
States in en_US locale: enabled,focusable,visible,showing,opaque
Index in parent: 1
Children count: 0
Bounding rectangle: [288, 317, 385, 376]
Top-level window name: Phone Assistant:
Top-level window role: frame
Parent name:
Parent role: panel
Visible descendents count: 0
AccessibleIcons info:
Number of icons: 1
Icon 0 description: jar:http://proxy.m5net.com/vox/pa/receptioncenter.jar!/resources/phone.png
Icon 0 height: 26
Icon 0 width: 27
AccessibleActions info:
Number of actions: 1
Action 0 name: click
Accessible Value information:
Current Value: 0
Maximum Value: 1
Minimum Value: 0
辅助功能文档告诉我,我应该告诉对象执行该操作,但我不知道如何执行此操作。
最好使用AutoHotkey,如何做到这一点?