Question

当我输入play时，会为number1分配一个随机数。它要求我进行预测，然后我输入一个数字，比如说5.输入5后我总是得到else语句而不是if语句。我甚至用print()来找出生成的数字。有时我在1或1之内（游戏也允许在1之内），它仍然会重新指向else语句。有人可以帮忙吗？感谢。

money = 1000000

def luckyrollgame():
    global money
    from random import choice
    print('You are in the game lobby of Lucky Roll.')
    print('Choose either \'rules,\' \'play,\' or \'back\'')
    lobby = input()
    if lobby == 'rules':
        luckyrollgamerules()
    if lobby == 'play':
        die = [1, 2, 3, 4, 5, 6]
        number1 = choice(die)
        prediction = input('Please type your prediction number: ')
        if prediction == number1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        if prediction == number1 - 1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        if prediction == number1 + 1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        else:
            print('I\'m sorry. You didn\'t get the number right.')
            print('The number was ' + str(number1) + '.')
            money = money - 1
            print('You now have ' + str(money) + 'dollars.')
            print('--------------------------------------------------')
            altluckyrollgame()
    if lobby == 'back':
        altvillagescene()
    else:
        print('Please type a valid option.')
        print('--------------------------------')
        altluckyrollgame()

* altluckyrollgame()或altvillagescene()等函数是游戏逻辑的一部分，并在别处定义，因此您可以忽略它们。

Answer 1

您的问题是您正在将字符串与整数进行比较。

您需要先将输入转换为int：

try:
    guess = int(prediction)
except ValueError:
    #Handle when a person enters an invalid number here

Answer 2

在第一个语句后使用elif语句。目前，您的代码

    if lobby == 'back':
        altvillagescene()
    else:
        print('Please type a valid option.')
        print('--------------------------------')
        altluckyrollgame()

正在检查lobby =='back'并在所有其他情况下运行else。您可能不希望这样，因为除了其他所有情况之外，其他地方的代码也会运行。

if x == 0: pass
elif x == 1: pass
else: pass

代码应如下所示

money = 1000000

def luckyrollgame():
    global money
    from random import choice
    print('You are in the game lobby of Lucky Roll.')
    print('Choose either \'rules,\' \'play,\' or \'back\'')
    lobby = input()
    if lobby == 'rules':
        luckyrollgamerules()
    elif lobby == 'play':
        die = [1, 2, 3, 4, 5, 6]
        number1 = choice(die)
        prediction = input('Please type your prediction number: ')
######################### This too
        try: prediction = int(prediction)
        except ValueError: prediction = -10
#########################
        if prediction == number1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        elif prediction == number1 - 1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        elif prediction == number1 + 1:
            print('Good job! You guessed right!')
            money = money + 3
            print('You now have ' + str(dollars) + 'dollars.')
        else:
            print('I\'m sorry. You didn\'t get the number right.')
            print('The number was ' + str(number1) + '.')
            money = money - 1
            print('You now have ' + str(money) + 'dollars.')
            print('--------------------------------------------------')
            altluckyrollgame()
    elif lobby == 'back':
        altvillagescene()
    else:
        print('Please type a valid option.')
        print('--------------------------------')
        altluckyrollgame()

Answer 3

prediction返回的input()是字符串，因此所有比较都会失败。尝试将值转换为整数：

prediction = int(input())

Answer 4

“else”块仅与最终的“if prediction == number1 + 1”匹配。这意味着如果猜到正确的数字（或数字1 - 1），那么它仍然会运行最后的其他块。

您需要更改代码以使用“elif”作为中间条件：

if prediction == number1:
   pass # do the win
elif prediction == number1 - 1
   pass # do the win
elif prediction == number1 + 1
   pass  # do the win
else:
   pass # do the lose

Answer 5

你有三种不同的if结构。你几乎肯定想要

if ...



elif ...

elif ...

else

条件总是计算到else分支

5 个答案: