我在使用predicateWithFormat时出错,导致我的应用程序崩溃。
有问题的代码是:
@implementation SecondViewController
{
NSArray *searchResults;
}
@synthesize jsonConnection, bakeryProductArray, bakeryTableView;
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
[self retrieveData];
}
- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
#pragma mark - UITableView DataSource
-(NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return 1;
}
-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
if (tableView == self.searchDisplayController.searchResultsTableView) {
return [searchResults count];
}
else {
return [bakeryProductArray count];
}
}
-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *cellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier];
if (cell == nil) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:cellIdentifier];
}
if (tableView == self.searchDisplayController.searchResultsTableView) {
cell.textLabel.text = [searchResults objectAtIndex:indexPath.row];
}
else {
foodProducts *currentProduct = [bakeryProductArray objectAtIndex:indexPath.row];
cell.textLabel.text = currentProduct.productName;
cell.detailTextLabel.text = currentProduct.productName;
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
}
return cell;
}
#pragma mark - UITableView Delegate methods
-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
if (bakeryTableView == self.searchDisplayController.searchResultsTableView) {
[self performSegueWithIdentifier: @"bakeryDetails" sender: self];
}
detailedViewController *productinfo = [self.storyboard instantiateViewControllerWithIdentifier:@"bakeryDetails"];
//Retrieve current user array
foodProducts *currentProduct2 = [bakeryProductArray objectAtIndex:indexPath.row];
productinfo.productName = currentProduct2.productName;
productinfo.productImage = currentProduct2.productImgUrl;
productinfo.productDescription = currentProduct2.productDescription;
productinfo.productPrice = currentProduct2.productPrice;
productinfo.productQuantity = currentProduct2.productquantity;
productinfo.productAllergy = currentProduct2.productAllergy;
[self.navigationController pushViewController:productinfo animated:YES];
[bakeryTableView deselectRowAtIndexPath:indexPath animated:YES];
}
//Becareful here as wrong predicateWithFormat can crash app on keying in search
-(void)filterContentForSearchText:(NSString *)searchText scope:(NSString *)scope
{
NSPredicate *resultPredicate = [NSPredicate predicateWithBlock:^BOOL(NSString * testString, NSDictionary *bindings) {
return ([searchText compare:testString options: NSCaseInsensitiveSearch] == NSOrderedSame);
}];
searchResults = [bakeryProductArray filteredArrayUsingPredicate:resultPredicate];
}
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller
shouldReloadTableForSearchString:(NSString *)searchString
{
[self filterContentForSearchText:searchString
scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
objectAtIndex:[self.searchDisplayController.searchBar
selectedScopeButtonIndex]]];
return YES;
}
#pragma mark - methods
-(void) retrieveData
{
NSURL *url = [NSURL URLWithString:getDataUrl];
NSData *data = [NSData dataWithContentsOfURL:url];
jsonConnection = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:nil];
bakeryProductArray = [[NSMutableArray alloc]init];
for (int i = 0; i < jsonConnection.count; i++)
{
NSString *pID = [[jsonConnection objectAtIndex:i] objectForKey:@"id"];
NSString *pName = [[jsonConnection objectAtIndex:i] objectForKey:@"Name"];
NSString *pImageUrl = [[jsonConnection objectAtIndex:i] objectForKey:@"ImageUrl"];
NSString *pDescription = [[jsonConnection objectAtIndex:i] objectForKey:@"Description"];
NSString *pQuantity = [[jsonConnection objectAtIndex:i] objectForKey:@"Quantity"];
NSString *pPrice = [[jsonConnection objectAtIndex:i] objectForKey:@"Price"];
NSString *pAllergy = [[jsonConnection objectAtIndex:i] objectForKey:@"Allergy"];
foodProducts *myProducts = [[foodProducts alloc]initWithproductID:pID andproductName:pName andproductImgUrl:pImageUrl andproductDescription:pDescription andproductquantity:pQuantity andproductPrice:pPrice andproductAllergy:pAllergy];
[bakeryProductArray addObject:myProducts];
}
[self.bakeryTableView reloadData];
}
FoodProduct类
@implementation foodProducts
@synthesize productID, productName, productImgUrl, productquantity,productDescription, productPrice, productAllergy;
-(id) initWithproductID:(NSString *)uproductID andproductName:(NSString *)uproductName andproductImgUrl:(NSString *)uproductImage andproductDescription:(NSString *)uproductDescription andproductquantity:(NSString *)uproductquantity andproductPrice:(NSString *)uproductPrice andproductAllergy:(NSString *)uproductAllergy
{
self = [super init];
if (self)
{
productID = uproductID;
productName = uproductName;
productImgUrl = uproductImage;
productquantity = uproductquantity;
productDescription = uproductDescription;
productPrice = uproductPrice;
productAllergy = uproductAllergy;
}
return self;
}
正在输入NSPredicate的数组是@property (nonatomic, strong) NSMutableArray *bakeryProductArray;
错误说:无法在集合中使用/ contains运算符
有什么想法,哪些是错的?
答案 0 :(得分:1)
您的数组不包含字符串,但包含自定义foodProducts
个对象。
要按“产品名称”过滤对象,请使用
[NSPredicate predicateWithFormat:@"productName CONTAINS[cd] %@", searchText];
已添加:您的代码中还有另一个错误:
cell.textLabel.text = [searchResults objectAtIndex:indexPath.row];
无法正常工作,因为右侧不会返回字符串。它应该是
foodProducts *currentProduct = [searchResults objectAtIndex:indexPath.row];
cell.textLabel.text = currentProduct.productName;
答案 1 :(得分:0)
NSPredicate * resultPredicate = [NSPredicate predicateWithFormat:@“self.productName包含[cd]%@”,searchText];
NSArray * searchResults = [self.bakeryProductArray filteredArrayUsingPredicate:resultPredicate];
的NSLog(@ “%@”,SearchResult所);
如果上述方法不起作用,您可以展示您的foodProduct类(型号)。
理想情况下,您应该使用[cd]而不是[cd]。
参考:http://developer.apple.com/library/ios/#documentation/cocoa/conceptual/Predicates/Articles/pSyntax.html 1包含 左手表达式包含右手表达式。
2喜欢 左手表达式等于右手表达式:?和*被允许作为通配符,在哪里?匹配1个字符,*匹配0个或更多个字符。