我需要将任意数量的毫秒转换为Days，Hours，Minutes Second。
例如：10天，5小时，13分钟，1秒。
答案 0 :(得分：221)
好吧，因为没有其他人加强，我会编写简单的代码来执行此操作：
x = ms / 1000
seconds = x % 60
x /= 60
minutes = x % 60
x /= 60
hours = x % 24
x /= 24
days = x
我很高兴你在几天停下来并没有问几个月。 ：）
注意，在上文中，假设/表示截断整数除法。如果以/表示浮点除法的语言使用此代码，则需要根据需要手动截断除法的结果。
答案 1 :(得分：56)
设A为毫秒数。然后你有：
seconds=(A/1000)%60
minutes=(A/(1000*60))%60
hours=(A/(1000*60*60))%24
等等（%是模数运算符）。
希望这有帮助。
答案 2 :(得分：24)
下面的两个解决方案都使用 javascript （我不知道解决方案是语言无关的！）。如果捕获持续时间> 1 month，则需要扩展这两种解决方案。
var date = new Date(536643021);
var str = '';
str += date.getUTCDate()-1 + " days, ";
str += date.getUTCHours() + " hours, ";
str += date.getUTCMinutes() + " minutes, ";
str += date.getUTCSeconds() + " seconds, ";
str += date.getUTCMilliseconds() + " millis";
console.log(str);
给出：
"6 days, 5 hours, 4 minutes, 3 seconds, 21 millis"
图书馆很有用，但为什么在你可以重新发明轮子时使用图书馆呢！ ：）
var getDuration = function(millis){
var dur = {};
var units = [
{label:"millis", mod:1000},
{label:"seconds", mod:60},
{label:"minutes", mod:60},
{label:"hours", mod:24},
{label:"days", mod:31}
];
// calculate the individual unit values...
units.forEach(function(u){
millis = (millis - (dur[u.label] = (millis % u.mod))) / u.mod;
});
// convert object to a string representation...
var nonZero = function(u){ return dur[u.label]; };
dur.toString = function(){
return units
.reverse()
.filter(nonZero)
.map(function(u){
return dur[u.label] + " " + (dur[u.label]==1?u.label.slice(0,-1):u.label);
})
.join(', ');
};
return dur;
};
使用您需要的任何字段创建“持续时间”对象。 格式化时间戳然后变得简单......
console.log(getDuration(536643021).toString());
给出：
"6 days, 5 hours, 4 minutes, 3 seconds, 21 millis"
答案 3 :(得分：20)
Apache Commons Lang有一个DurationFormatUtils，其中包含非常有用的方法，例如formatDurationWords。
答案 4 :(得分：7)
你应该使用你正在使用的任何语言的日期时间函数，但是，这里只是为了好玩的代码：
int milliseconds = someNumber;
int seconds = milliseconds / 1000;
int minutes = seconds / 60;
seconds %= 60;
int hours = minutes / 60;
minutes %= 60;
int days = hours / 24;
hours %= 24;
答案 5 :(得分：4)
function convertTime(time) {
var millis= time % 1000;
time = parseInt(time/1000);
var seconds = time % 60;
time = parseInt(time/60);
var minutes = time % 60;
time = parseInt(time/60);
var hours = time % 24;
var out = "";
if(hours && hours > 0) out += hours + " " + ((hours == 1)?"hr":"hrs") + " ";
if(minutes && minutes > 0) out += minutes + " " + ((minutes == 1)?"min":"mins") + " ";
if(seconds && seconds > 0) out += seconds + " " + ((seconds == 1)?"sec":"secs") + " ";
if(millis&& millis> 0) out += millis+ " " + ((millis== 1)?"msec":"msecs") + " ";
return out.trim();
}
答案 6 :(得分：4)
这是我写的一种方法。它需要integer milliseconds value并返回human-readable String：
public String convertMS(int ms) {
int seconds = (int) ((ms / 1000) % 60);
int minutes = (int) (((ms / 1000) / 60) % 60);
int hours = (int) ((((ms / 1000) / 60) / 60) % 24);
String sec, min, hrs;
if(seconds<10) sec="0"+seconds;
else sec= ""+seconds;
if(minutes<10) min="0"+minutes;
else min= ""+minutes;
if(hours<10) hrs="0"+hours;
else hrs= ""+hours;
if(hours == 0) return min+":"+sec;
else return hrs+":"+min+":"+sec;
}
答案 7 :(得分：2)
Long serverUptimeSeconds =
(System.currentTimeMillis() - SINCE_TIME_IN_MILLISECONDS) / 1000;
String serverUptimeText =
String.format("%d days %d hours %d minutes %d seconds",
serverUptimeSeconds / 86400,
( serverUptimeSeconds % 86400) / 3600 ,
((serverUptimeSeconds % 86400) % 3600 ) / 60,
((serverUptimeSeconds % 86400) % 3600 ) % 60
);
答案 8 :(得分：2)
您的选择很简单：
答案 9 :(得分：2)
我建议使用您选择的语言/框架提供的日期/时间函数/库。还要检查字符串格式化函数，因为它们通常提供简单的方法来传递日期/时间戳并输出人类可读的字符串格式。
答案 10 :(得分：2)
Long expireTime = 69l;
Long tempParam = 0l;
Long seconds = math.mod(expireTime, 60);
tempParam = expireTime - seconds;
expireTime = tempParam/60;
Long minutes = math.mod(expireTime, 60);
tempParam = expireTime - minutes;
expireTime = expireTime/60;
Long hours = math.mod(expireTime, 24);
tempParam = expireTime - hours;
expireTime = expireTime/24;
Long days = math.mod(expireTime, 30);
system.debug(days + '.' + hours + ':' + minutes + ':' + seconds);
这应该打印：0.0：1：9
答案 11 :(得分：2)
为什么不做这样的事情：
var ms = 86400;
var seconds = ms / 1000; //86.4
var minutes = seconds / 60; //1.4400000000000002
var hours = minutes / 60; //0.024000000000000004
var days = hours / 24; //0.0010000000000000002
处理浮点精度，例如编号（minutes.toFixed（5））// 1.44
答案 12 :(得分：2)
在java中
public static String formatMs(long millis) {
long hours = TimeUnit.MILLISECONDS.toHours(millis);
long mins = TimeUnit.MILLISECONDS.toMinutes(millis);
long secs = TimeUnit.MILLISECONDS.toSeconds(millis);
return String.format("%dh %d min, %d sec",
hours,
mins - TimeUnit.HOURS.toMinutes(hours),
secs - TimeUnit.MINUTES.toSeconds(mins)
);
}
给出这样的东西：
12h 1 min, 34 sec
答案 13 :(得分：1)
我无法评论你的问题的第一个答案，但是有一个小错误。您应该使用parseInt或Math.floor将浮点数转换为整数，i
var days, hours, minutes, seconds, x;
x = ms / 1000;
seconds = Math.floor(x % 60);
x /= 60;
minutes = Math.floor(x % 60);
x /= 60;
hours = Math.floor(x % 24);
x /= 24;
days = Math.floor(x);
就个人而言，我在我的项目中使用CoffeeScript，我的代码看起来像这样：
getFormattedTime : (ms)->
x = ms / 1000
seconds = Math.floor x % 60
x /= 60
minutes = Math.floor x % 60
x /= 60
hours = Math.floor x % 24
x /= 24
days = Math.floor x
formattedTime = "#{seconds}s"
if minutes then formattedTime = "#{minutes}m " + formattedTime
if hours then formattedTime = "#{hours}h " + formattedTime
formattedTime
答案 14 :(得分：1)
这是一个解决方案。稍后您可以通过“：”拆分并获取数组的值
/**
* Converts milliseconds to human readeable language separated by ":"
* Example: 190980000 --> 2:05:3 --> 2days 5hours 3min
*/
function dhm(t){
var cd = 24 * 60 * 60 * 1000,
ch = 60 * 60 * 1000,
d = Math.floor(t / cd),
h = '0' + Math.floor( (t - d * cd) / ch),
m = '0' + Math.round( (t - d * cd - h * ch) / 60000);
return [d, h.substr(-2), m.substr(-2)].join(':');
}
var delay = 190980000;
var fullTime = dhm(delay);
console.log(fullTime);
答案 15 :(得分：1)
这是我使用TimeUnit的解决方案。
更新：我应该指出这是用groovy编写的，但Java几乎完全相同。
def remainingStr = ""
/* Days */
int days = MILLISECONDS.toDays(remainingTime) as int
remainingStr += (days == 1) ? '1 Day : ' : "${days} Days : "
remainingTime -= DAYS.toMillis(days)
/* Hours */
int hours = MILLISECONDS.toHours(remainingTime) as int
remainingStr += (hours == 1) ? '1 Hour : ' : "${hours} Hours : "
remainingTime -= HOURS.toMillis(hours)
/* Minutes */
int minutes = MILLISECONDS.toMinutes(remainingTime) as int
remainingStr += (minutes == 1) ? '1 Minute : ' : "${minutes} Minutes : "
remainingTime -= MINUTES.toMillis(minutes)
/* Seconds */
int seconds = MILLISECONDS.toSeconds(remainingTime) as int
remainingStr += (seconds == 1) ? '1 Second' : "${seconds} Seconds"
答案 16 :(得分：1)
灵活的方式：
（不是针对当前日期而是针对持续时间做得足够好）
/**
convert duration to a ms/sec/min/hour/day/week array
@param {int} msTime : time in milliseconds
@param {bool} fillEmpty(optional) : fill array values even when they are 0.
@param {string[]} suffixes(optional) : add suffixes to returned values.
values are filled with missings '0'
@return {int[]/string[]} : time values from higher to lower(ms) range.
*/
var msToTimeList=function(msTime,fillEmpty,suffixes){
suffixes=(suffixes instanceof Array)?suffixes:[]; //suffixes is optional
var timeSteps=[1000,60,60,24,7]; // time ranges : ms/sec/min/hour/day/week
timeSteps.push(1000000); //add very big time at the end to stop cutting
var result=[];
for(var i=0;(msTime>0||i<1||fillEmpty)&&i<timeSteps.length;i++){
var timerange = msTime%timeSteps[i];
if(typeof(suffixes[i])=="string"){
timerange+=suffixes[i]; // add suffix (converting )
// and fill zeros :
while( i<timeSteps.length-1 &&
timerange.length<((timeSteps[i]-1)+suffixes[i]).length )
timerange="0"+timerange;
}
result.unshift(timerange); // stack time range from higher to lower
msTime = Math.floor(msTime/timeSteps[i]);
}
return result;
};
注意：如果要控制时间范围，也可以将 timeSteps 设置为参数。
如何使用（复制测试）：
var elsapsed = Math.floor(Math.random()*3000000000);
console.log( "elsapsed (labels) = "+
msToTimeList(elsapsed,false,["ms","sec","min","h","days","weeks"]).join("/") );
console.log( "half hour : "+msToTimeList(elsapsed,true)[3]<30?"first":"second" );
console.log( "elsapsed (classic) = "+
msToTimeList(elsapsed,false,["","","","","",""]).join(" : ") );
答案 17 :(得分：1)
我建议使用http://www.ocpsoft.org/prettytime/库..
以人类可读的形式获得时间间隔非常简单，如
PrettyTime p = new PrettyTime();
System.out.println(p.format(new Date()));
它会打印出“从现在开始的时刻”
其他例子
PrettyTime p = new PrettyTime());
Date d = new Date(System.currentTimeMillis());
d.setHours(d.getHours() - 1);
String ago = p.format(d);
then string ago =“1小时前”
答案 18 :(得分：0)
这是JAVA中更精确的方法，我已经实现了这个简单的逻辑，希望这会对你有所帮助：
public String getDuration(String _currentTimemilliSecond)
{
long _currentTimeMiles = 1;
int x = 0;
int seconds = 0;
int minutes = 0;
int hours = 0;
int days = 0;
int month = 0;
int year = 0;
try
{
_currentTimeMiles = Long.parseLong(_currentTimemilliSecond);
/** x in seconds **/
x = (int) (_currentTimeMiles / 1000) ;
seconds = x ;
if(seconds >59)
{
minutes = seconds/60 ;
if(minutes > 59)
{
hours = minutes/60;
if(hours > 23)
{
days = hours/24 ;
if(days > 30)
{
month = days/30;
if(month > 11)
{
year = month/12;
Log.d("Year", year);
Log.d("Month", month%12);
Log.d("Days", days % 30);
Log.d("hours ", hours % 24);
Log.d("Minutes ", minutes % 60);
Log.d("Seconds ", seconds % 60);
return "Year "+year + " Month "+month%12 +" Days " +days%30 +" hours "+hours%24 +" Minutes "+minutes %60+" Seconds "+seconds%60;
}
else
{
Log.d("Month", month);
Log.d("Days", days % 30);
Log.d("hours ", hours % 24);
Log.d("Minutes ", minutes % 60);
Log.d("Seconds ", seconds % 60);
return "Month "+month +" Days " +days%30 +" hours "+hours%24 +" Minutes "+minutes %60+" Seconds "+seconds%60;
}
}
else
{
Log.d("Days", days );
Log.d("hours ", hours % 24);
Log.d("Minutes ", minutes % 60);
Log.d("Seconds ", seconds % 60);
return "Days " +days +" hours "+hours%24 +" Minutes "+minutes %60+" Seconds "+seconds%60;
}
}
else
{
Log.d("hours ", hours);
Log.d("Minutes ", minutes % 60);
Log.d("Seconds ", seconds % 60);
return "hours "+hours+" Minutes "+minutes %60+" Seconds "+seconds%60;
}
}
else
{
Log.d("Minutes ", minutes);
Log.d("Seconds ", seconds % 60);
return "Minutes "+minutes +" Seconds "+seconds%60;
}
}
else
{
Log.d("Seconds ", x);
return " Seconds "+seconds;
}
}
catch (Exception e)
{
Log.e(getClass().getName().toString(), e.toString());
}
return "";
}
private Class Log
{
public static void d(String tag , int value)
{
System.out.println("##### [ Debug ] ## "+tag +" :: "+value);
}
}
答案 19 :(得分：0)
使用awk的解决方案：
$ ms=10000001; awk -v ms=$ms 'BEGIN {x=ms/1000;
s=x%60; x/=60;
m=x%60; x/=60;
h=x%60;
printf("%02d:%02d:%02d.%03d\n", h, m, s, ms%1000)}'
02:46:40.001
答案 20 :(得分：0)
在python 3中，您可以使用以下代码段实现目标：
from datetime import timedelta
ms = 536643021
td = timedelta(milliseconds=ms)
print(str(td))
# --> 6 days, 5:04:03.021000
Timedelta文档：https://docs.python.org/3/library/datetime.html#datetime.timedelta
timedelta str的__str__方法的来源：https://github.com/python/cpython/blob/33922cb0aa0c81ebff91ab4e938a58dfec2acf19/Lib/datetime.py#L607