我在actions.class.php
:
public function executeIndex(sfWebRequest $request) {
$id_empresa = $this->getUser()->getGuardUser()->getSfGuardUserProfile()->getIdempresa();
$this->records = Doctrine_Core::getTable('SdrivingRegistrosEmisores')
->createQuery('re')
->leftJoin('re.SdrivingTurno t')
->leftJoin('re.SdrivingMaquinaEmisor me')
->leftJoin('me.SdrivingMaquina m')
->leftJoin('re.SdrivingOperador o')
->leftJoin('re.SdrivingDetalleEmisores de')
->where('o.idempresa = ?', $id_empresa)
->execute();
}
呈现此视图:
<table class="table table-condensed table-striped table-hover table-bordered pull-left" id="data-table">
<thead>
<tr>
<th><?php echo __('Turno') ?></th>
<th><?php echo __('ID Máquina') ?></th>
<th><?php echo __('Operador') ?></th>
<th><?php echo __('Semáforo') ?></th>
<th> </th>
</tr>
</thead>
<tbody>
<?php foreach ($records as $record): ?>
<tr>
<td><?php echo $record->SdrivingTurno->getTipo(); ?></td>
<td><?php echo $record->SdrivingMaquinaEmisor->SdrivingMaquina->getPatente(); ?></td>
<td><?php echo $record->SdrivingOperador->getNombre() ?></td>
<td>
<?php
if (count($record->SdrivingDetalleEmisores) > 0):
if ($record->SdrivingDetalleEmisores->getFirst()->getRevisado() == 0):
echo image_tag('bullet_red.png');
elseif ($record->SdrivingDetalleEmisores->getFirst()->getRevisado() == 1):
echo image_tag('bullet_orange.png');
endif;
else:
echo image_tag('bullet_green.png');
endif;
?>
</td>
<td><?php echo link_to('Ver detalles', 'ver-detalles/' . $record->getIdregistros(), 'class="btn btn-success btn-mini"') ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
正如标题所说我需要每10秒重新加载一次表格内容,在Stackoverflow和Google中挖掘我发现这个topic我可以获得jQuery代码但我的问题是:如何更新每一行在表格HTML元素?
修改
阅读后推荐后,请用户离开这里,这是我迄今为止尝试过的,但没有成功:
actions.class.php
public function executebuildAjax(sfWebRequest $request) {
$id_empresa = $this->getUser()->getGuardUser()->getSfGuardUserProfile()->getIdempresa();
$records = Doctrine_Core::getTable('SdrivingRegistrosEmisores')
->createQuery('re')
->leftJoin('re.SdrivingTurno t')
->leftJoin('re.SdrivingMaquinaEmisor me')
->leftJoin('me.SdrivingMaquina m')
->leftJoin('re.SdrivingOperador o')
->leftJoin('re.SdrivingDetalleEmisores de')
->where('o.idempresa = ?', $id_empresa)
->execute();
echo '<table class="table table-condensed table-striped table-hover table-bordered pull-left" id="data-table">';
echo '<thead>';
echo '<tr>';
echo '<th>' . __('Turno') . '</th>';
echo '<th>' . __('ID Máquina') . '</th>';
echo '<th>' . __('Operador') . '</th>';
echo '<th>' . __('Semáforo') . '</th>';
echo '<th></th>';
echo '</tr>';
echo '<tbody>';
foreach ($records as $record):
echo '<tr>';
echo '<td>' . $record->SdrivingTurno->getTipo() . '</td>';
echo '<td>' . $record->SdrivingMaquinaEmisor->SdrivingMaquina->getPatente() . '</td>';
echo '<td>' . $record->SdrivingOperador->getNombre() . '</td>';
echo '<td>';
if (count($record->SdrivingDetalleEmisores) > 0):
if ($record->SdrivingDetalleEmisores->getFirst()->getRevisado() == 0):
echo image_tag('bullet_red.png');
elseif ($record->SdrivingDetalleEmisores->getFirst()->getRevisado() == 1):
echo image_tag('bullet_orange.png');
endif;
else:
echo image_tag('bullet_green.png');
endif;
echo '</td>';
echo '<td>' . link_to('Ver detalles', 'ver-detalles/' . $record->getIdregistros(), 'class="btn btn-success btn-mini"') . '</th>';
echo '</tr>';
endforeach;
echo '</tbody>';
echo '</thead>';
echo '</table>';
}
indexSuccess.php
查看:
<div id="dt_example" class="example_alt_pagination"></div>
<script>
$(document).ready(function() {
setInterval(function() {
$.ajax({
type: 'get',
url: '<?php echo url_for('dashboard/buildAjax') ?>',
datatype: 'html',
success: function(data) {
$("#dt_example").html(data);
},
error: function() {
alert('<?php echo __('Error loading data!!!') ?>');
}
});
}, 10000);
});
</script>
但是我总是得到警告框加载数据时出错!!! 为什么?有什么问题?
答案 0 :(得分:3)
我建议您使用ajax和setInterval函数从服务器请求表并替换客户端的HTML。
这个答案非常接近您的需求:jQuery - Call ajax every 10 seconds
答案 1 :(得分:0)
你应该在行动中归还一些东西。 例如,使用您的表制作部分(_table.php) 在indexSuccess中你应该有
<div id="table">
<?php include_partial('module/table', array('records' => $records))?>
</div>
在ajax操作中,您应该从数据库获取数据并返回此部分
$records = Query:...;
$html = $this->getPartial('module/table', array('records' => $records));
return $this->renderText($html);
或者更好地使用json
return $this->renderText(json_encode(array('html' => $html)))
然后使用ajax成功函数将结果插入div:
success: function(data){
$('#table').html(data.html)
}