Question

我有以下代码返回当前作业及其估计时间的数据透视表：

DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);

select @cols = STUFF((SELECT distinct ',' +
                    QUOTENAME(Name)
                  FROM JobPhases
                  FOR XML PATH(''), TYPE
                 ).value('.', 'NVARCHAR(MAX)') 
                    , 1, 1, '');

SELECT @query = 'SELECT *
FROM    
(   
    SELECT c.Registration as ''Reg.'', p.Name, [x] = j.EstimatedTime
    FROM    JobDetails  AS j
    INNER JOIN JobPhases p ON p.ID = j.PhaseId
    INNER JOIN Jobs job on job.ID = j.JobID
    INNER JOIN Cars c on job.CarID = c.ID
    WHERE job.Status = 1 or job.Status = 0
) JobDetails
PIVOT
(   SUM(x)
    FOR Name IN (' + @cols + ')
) pvt'

execute(@query);

输出：

JobID | Repair & Reshape | Refit Stripped Parts | Polishing 
1000  | 2.00             | 1.00                 | 1.30
1001  | 2.30             | 0.30                 | 2.00

我需要的是在显示的值中连接j.ActualTime。我有什么想法可以做到这一点？因此，最终输出为- 4.00 / 5.30（其中4.00为j.EstimatedTime，5.30为j.ActualTime）。

干杯

Answer 1

我会先在PIVOT之外进行所有处理。这样您就可以进行聚合，连接以及任何您想要的操作。完成所有处理后，再进行一个简单的非聚合支点：

SELECT *
FROM    
(   
    SELECT c.Registration as ''Reg.'', p.Name, 
        CAST(SUM(j.EstimatedTime) as VARCHAR(MAX)) + '/' +
        CAST(SUM(j.ActualTime) as VARCHAR(MAX)) as [x]
    FROM    JobDetails  AS j
    INNER JOIN JobPhases p ON p.ID = j.PhaseId
    INNER JOIN Jobs job on job.ID = j.JobID
    INNER JOIN Cars c on job.CarID = c.ID
    WHERE job.Status = 1 or job.Status = 0
    GROUP BY c.Registration, p.Name
) JobDetails
PIVOT
(   MAX(x)
    FOR Name IN (' + @cols + ')
) pvt

连接数据透视表输出

1 个答案: