从unix中从特定单词到最后一列的行中选择列？

Question

输入文件

1. blue is color
2. His shirt color is blue and it is good
3. deep blue see is a movie

输出：

1. blue is color
2. blue and it is good
3. blue see is a movie

我需要输出从unix中的特定单词到最后一列，使用awk或cut。

Answer 1

awk 'BEGIN{FS="\\<blue\\>"; OFS="blue"}{$1=""}7' file

以上行将输出：

kent$  awk 'BEGIN{FS="\\<blue\\>"; OFS="blue"}{$1=""}7' file                                                                                                                   
blue is color
blue and it is good
blue see is a movie

请注意，"\\<blue\\>"将完全匹配单词blue，而不是bluesky or darkblue我希望这是您想要的。

Answer 2

sed的代码：

$ sed -r 's/^([0-9]+. ).* (blue)\b/\1\2/' file
1. blue is color
2. blue and it is good
3. blue see is a movie

Answer 3

这是一个很常见的用例，

cat test.txt | awk '{ if (x=index($0,"blue")) { print substr($0,x,length($0)); } }'

我建议你看看Awk - A Tutorial and Introduction

Answer 4

Perl：

perl -nle'/(blue.*)/&&print"$1\n"'