Question

我目前正在通过教程学习PHP，我正在尝试运行以下代码，但是得到了一个无法解释的语法错误，而其他人似乎没有发现这些错误。

错误消息 解析错误：语法错误，意外＆＃39 ;;＆＃39;在第12行的.... / users.php

第12行=

return (mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id');

整页代码

<?php
function user_exists($username) {
$username = sanitize($username);
return (mysql_result(mysql_query("SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username'"), 0) == 1) ? true : false;
}
function user_active($username) {
$username = sanitize($username);
return (mysql_result(mysql_query("SELECT COUNT(`user_id`) FROM `users` WHERE `username`    = '$username' AND `active` =1"), 0) ==1) ? true : false;
}
function user_id_from_username ($username) {
$username = sanitize($username);
return (mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id');
}
function login ($username, $password) {
$user_id = user_id_from_username($username);

$username = sanitize($username);
$password = md5($password);

return(mysql_result(mysql_query("SELECT COUNT (`user_id`) FROM `users` WHERE `username` = '$username' AND `password` = '$password'"), 0) == 1) ? $user_id : false;


}
?>

Answer 1

你错过了一个右括号）你有3个开场但只有2个关闭...

Answer 2

还有一个封闭的圆形支架。

                                                           /* v */
return (mysql_result(mysql_query("..."), 0, 'user_id')/* -> */)/* <- */;
                                                           /* ^ */

Answer 3

试试这个，

function user_id_from_username ($username) {
    $username = sanitize($username);
    return (mysql_result(
          mysql_query(
                "SELECT `user_id` FROM `users` WHERE `username` = '$username'"
           ), 0
    ), 'user_id');
}

无法弄清楚这种语法错误是什么

3 个答案: