每条记录最多可包含40个不同的person_user.description字段。问题是，我得到重复的行，因为记录有多个描述条目。你能帮我把这些额外的副本放在同一个记录行上，如：
| 1 | badge.bid | person.first_name | person.last_name | person.type | 1 | 2 | 3 | 4 | 5 |等| 40 | | 2 | badge.bid | person.first_name | person.last_name | person.type | 1 | 2 | 3 | 4 | 5 |等| 40 | | 3 | badge.bid | person.first_name | person.last_name | person.type | 1 | 2 | 3 | 4 | 5 |等| 40 |
而不是：
| 1 | badge.bid | person.first_name | person.last_name | person.type | person_user.description | | 1 | badge.bid | person.first_name | person.last_name | person.type | person_user.description | | 2 | badge.bid | person.first_name | person.last_name | person.type | person_user.description | | 2 | badge.bid | person.first_name | person.last_name | person.type | person_user.description |
SELECT person.id,
badge.bid,
person.first_name,
person.last_name,
person.type,
person_user.description
FROM person,
badge,
person_user
WHERE person.id = badge.id
AND person.id = person_user.person_id
AND badge.bid NOT LIKE "111%"
AND badge.access_date >= 20130401
GROUP BY person.id,
badge.bid,
person.first_name,
person.last_name,
person.type,
person_user.description
ORDER BY person.id
答案 0 :(得分：1)
弄清楚了。这就是我顺便实现它的方式。
SELECT P.id,
B.bid,
P.first_name,
P.last_name,
PT.description,
PU1.description PU1,
PU2.description PU2,
PU3.description PU3,
PU4.description PU4,
PU5.description PU5,
PU6.description PU6,
PU7.description PU7,
PU8.description PU8,
PU9.description PU9,
PU10.description PU10,
PU11.description PU11,
PU12.description PU12,
PU13.description PU13,
PU14.description PU14,
PU15.description PU15,
PU16.description PU16,
PU17.description PU17,
PU18.description PU18,
PU19.description PU19,
PU20.description PU20,
PU21.description PU21,
PU22.description PU22,
PU23.description PU23,
PU24.description PU24,
PU25.description PU25,
PU26.description PU26,
PU27.description PU27,
PU28.description PU28,
PU29.description PU29,
PU30.description PU30,
PU31.description PU31,
PU32.description PU32,
PU33.description PU33,
PU34.description PU34,
PU35.description PU35,
PU36.description PU36,
PU37.description PU37,
PU38.description PU38,
PU39.description PU39,
PU40.description PU40
FROM person P,
OUTER badge B,
person_type PT,
OUTER person_user PU1,
OUTER person_user PU2,
OUTER person_user PU3,
OUTER person_user PU4,
OUTER person_user PU5,
OUTER person_user PU6,
OUTER person_user PU7,
OUTER person_user PU8,
OUTER person_user PU9,
OUTER person_user PU10,
OUTER person_user PU11,
OUTER person_user PU12,
OUTER person_user PU13,
OUTER person_user PU14,
OUTER person_user PU15,
OUTER person_user PU16,
OUTER person_user PU17,
OUTER person_user PU18,
OUTER person_user PU19,
OUTER person_user PU20,
OUTER person_user PU21,
OUTER person_user PU22,
OUTER person_user PU23,
OUTER person_user PU24,
OUTER person_user PU25,
OUTER person_user PU26,
OUTER person_user PU27,
OUTER person_user PU28,
OUTER person_user PU29,
OUTER person_user PU30,
OUTER person_user PU31,
OUTER person_user PU32,
OUTER person_user PU33,
OUTER person_user PU34,
OUTER person_user PU35,
OUTER person_user PU36,
OUTER person_user PU37,
OUTER person_user PU38,
OUTER person_user PU39,
OUTER person_user PU40
WHERE P.id=B.person_id
AND P.type=PT.id
AND (P.id=PU1.person_id
AND PU1.slot_number=1)
AND (P.id=PU2.person_id
AND PU2.slot_number=2)
AND (P.id=PU3.person_id
AND PU3.slot_number=3)
AND (P.id=PU4.person_id
AND PU4.slot_number=4)
AND (P.id=PU5.person_id
AND PU5.slot_number=5)
AND (P.id=PU6.person_id
AND PU6.slot_number=6)
AND (P.id=PU7.person_id
AND PU7.slot_number=7)
AND (P.id=PU8.person_id
AND PU8.slot_number=8)
AND (P.id=PU9.person_id
AND PU9.slot_number=9)
AND (P.id=PU10.person_id
AND PU10.slot_number=10)
AND (P.id=PU11.person_id
AND PU11.slot_number=11)
AND (P.id=PU12.person_id
AND PU12.slot_number=12)
AND (P.id=PU13.person_id
AND PU13.slot_number=13)
AND (P.id=PU14.person_id
AND PU14.slot_number=14)
AND (P.id=PU15.person_id
AND PU15.slot_number=15)
AND (P.id=PU16.person_id
AND PU16.slot_number=16)
AND (P.id=PU17.person_id
AND PU17.slot_number=17)
AND (P.id=PU18.person_id
AND PU18.slot_number=18)
AND (P.id=PU19.person_id
AND PU19.slot_number=19)
AND (P.id=PU20.person_id
AND PU20.slot_number=20)
AND (P.id=PU21.person_id
AND PU21.slot_number=21)
AND (P.id=PU22.person_id
AND PU22.slot_number=22)
AND (P.id=PU23.person_id
AND PU23.slot_number=23)
AND (P.id=PU24.person_id
AND PU24.slot_number=24)
AND (P.id=PU25.person_id
AND PU25.slot_number=25)
AND (P.id=PU26.person_id
AND PU26.slot_number=26)
AND (P.id=PU27.person_id
AND PU27.slot_number=27)
AND (P.id=PU28.person_id
AND PU28.slot_number=28)
AND (P.id=PU29.person_id
AND PU29.slot_number=29)
AND (P.id=PU30.person_id
AND PU30.slot_number=30)
AND (P.id=PU31.person_id
AND PU31.slot_number=31)
AND (P.id=PU32.person_id
AND PU32.slot_number=32)
AND (P.id=PU33.person_id
AND PU33.slot_number=33)
AND (P.id=PU34.person_id
AND PU34.slot_number=34)
AND (P.id=PU35.person_id
AND PU35.slot_number=35)
AND (P.id=PU36.person_id
AND PU36.slot_number=36)
AND (P.id=PU37.person_id
AND PU37.slot_number=37)
AND (P.id=PU38.person_id
AND PU38.slot_number=38)
AND (P.id=PU39.person_id
AND PU39.slot_number=39)
AND (P.id=PU40.person_id
AND PU40.slot_number=40)
AND B.status=0
AND B.bid NOT LIKE "111%"
AND B.access_date>=20130401
ORDER BY P.id,
P.last_name
答案 1 :(得分：0)
您可以使用listagg（）函数来摆脱多行问题;但是，它不会像您在问题中描述的那样将每个描述放在单独的列中。相反，它会将所有描述放在一个列中，作为由您指定的字符分隔的字符串。以下示例将使用逗号和空格分隔描述：
SELECT person.id,
badge.bid,
person.first_name,
person.last_name,
person.type,
listagg(person_user.description, ', ') within group (order by person_user.description)
FROM person,
badge,
person_user
WHERE person.id = badge.id
AND person.id = person_user.person_id
AND badge.bid NOT LIKE "111%"
AND badge.access_date >= 20130401
GROUP BY person.id,
badge.bid,
person.first_name,
person.last_name,
person.type
ORDER BY person.id
答案 2 :(得分：0)
要实现这一点，在Informix中，您需要在these instructions之后定义自己的聚合函数。