Question

以下方法有时无法捕获数据。我相信这是因为.ready（）函数。

我们通过睡觉来破解它，但我不认为它是完全证据，看起来像是一个糟糕的黑客。

您是否可以就如何修复此方法提出建议，以便在完全读取请求时它可以正常工作？

提前致谢

/**
     * Parses a client request and calls the appropriate handler
     * @throws Exception
     */
    private void processClientRequest() throws Exception{
            Socket connectedClient = null;
        BufferedReader clientRequest = new BufferedReader(new InputStreamReader(connectedClient.getInputStream()));

        System.out.println(clientRequest);
        String requestString = clientRequest.readLine();

        String header = requestString;

        //Break up request
        StringTokenizer tokenizer = new StringTokenizer(header);

        //Different request parts
        String httpMethod = tokenizer.nextToken();
        String httpQueryString = tokenizer.nextToken();

        //Print client request
        StringBuffer responseBuffer = new StringBuffer();

        //Sleep to bypass weird clientRequest.ready() error
        if (httpMethod.equals("POST")) {
            Thread.sleep(100);
        }

        while (clientRequest.ready()) {
            responseBuffer.append(requestString + " ");
            System.out.println(requestString);

            requestString = clientRequest.readLine();
        }

        //Process GET request
        if (httpMethod.equals("GET")) {
            processGETRequests(httpQueryString, requestString);


        }else if (httpMethod.equals("POST")) {
            processPOSTRequests(responseBuffer, httpQueryString);
        }
    }

Answer 1

使用字符串时，您必须始终同意编码，并且永远不要使用默认值。在你的

// use wathever charset encoding you know is pressent on the socket stream like UTF-8
new InputStreamReader(socket.getInputStream(), "US-ASCII")

您不需要调用ready方法，readLine（）方法将阻塞，直到有一个新行被读取。你应该

while ((requestString = clientRequest.readLine()) != null) {
    // ...
}

Bufferedreader就绪方法丢失数据

1 个答案: