Question

我正在尝试显示与其类别相关的所有游戏，我在这里尝试的Sql只显示与游戏相关的游戏5，如何自动显示所有游戏？

<?php
$varCategoria_GameData = "0";
if (isset($_GET["cat"])) {
 $varCategoria_GameData = $_GET["cat"];
}

$sql_categoria = "SELECT * FROM jogos WHERE intCategoria =
( SELECT intCategoria FROM jogos WHERE idGames = 5)";
$query_categoria = mysql_query($sql_categoria, $gameconnection) or die(mysql_error()); 
$categoria = mysql_fetch_assoc($query_categoria);



 ?>


<?php  do { ?> 
<?php echo '<h1>'.$categoria['idGames'].'</h1>'; ?>
 <?php } while ($categoria = mysql_fetch_assoc($query_categoria)); ?>

Answer 1

您要从

中删除“WHERE idGames = 5”

$sql_categoria = "SELECT * FROM jogos";

查询以“WHERE idGames = 5”结尾，这实际上意味着它所说的内容。

然后你可以用这种方式从$ categoria中提取字段：

$categoria['name_of_field'];

意大利语：

Devi togliere“WHERE idGames = 5”e farlarisultaresosì：

$sql_categoria = "SELECT * FROM jogos";

Quello chiede allaqueryè

“SELECT intCategoria FROM jogos WHERE idGames = 5”; SELEZIONA intCategoria DA jogos DOVEidGamesè5

Poi da $ categoria puoi estrarre i campi in questo modo：

$categoria['nome_del_campo'];

Answer 2

<?php     
    $sql_categoria = "SELECT * FROM jogos";
    $result_categoria = mysql_query($sql_categoria, $gameconnection) or die(mysql_error()); 
    while($row = mysql_fetch_assoc($result_categoria))
    {
        //Use $row with the index of the field you want to display, or directly with the column name between quote.
        echo "Result :".$row[0]."<br />";
    }
?>

另外，使用MySQLi函数：http://php.net/manual/fr/book.mysqli.php

避免SQL注入更安全

在同一页面中显示一行的所有结果

2 个答案: