Question

所以即时尝试从复选框中插入选中的值，但不起作用。我相信我的问题是他们没有在开始时正确设置。我试图使用一个循环，但我相信我做错了：P

我的“isset”：

if(!empty($_POST))
{

    if(empty($_POST['name'])) {die("Please enter a Your Name.");}
    if(empty($_POST['ckboxes[]'])) {die("Please check at least one box.");}
    if(empty($_POST['ddown'])) {die("Please select a value.");}
    if(empty($_POST['txtDate'])) {die("Please type in a date.");}
    if(empty($_POST['agdis'])) {die("Please agree or disagree.");}
    if(empty($_POST['yn'])) {die("Please select Yes or No.");}

和插入过程：

//Insert for Checkboxes//
    /////////////////////////
    $query2 = "
        INSERT INTO coffee_ckbx (
            white,
            green,
            red,
            blue
        ) VALUES (
            :white,
            :green,
            :red,
            :blue   
        )
    ";

    foreach($_POST['ckboxes'] as $check){array($check);}

    $query_params2 = array(
        ':white' => $check['1'],
        ':green' => $check['2'],
        ':red' => $check['4'],
        ':blue' => $check['5']
    );

    try
    {
        // Execute the query to create the user
        $stmt = $db->prepare($query);
        $result = $stmt->execute($query_params);

        $stmt2 = $db->prepare($query2);
        $result2 = $stmt2->execute($query_params2);
    }
    //kept the catch out and other code due to lengthiness.

这是我的HTML：

            <li>
            <label for='ck-boxes'>Select from the check boxes: </label>
            <input type="hidden" name="ckboxes" value="0" />
            <input type='checkbox' id='' name='ckboxes' value='white'/>
            <input type='checkbox' id='' name='ckboxes' value='green'/>
            <input type='checkbox' id='' name='ckboxes' value='red'/>
            <input type='checkbox' id='' name='ckboxes' value='blue'/>
        </li>

有什么想法吗？提前谢谢你：）

Answer 1

尝试将[]添加到名称的末尾，这样就会告诉PHP这是一个数组。

<input type="hidden" name="ckboxes[]" value="0" />
<input type='checkbox' id='' name='ckboxes[]' value='white'/>
<input type='checkbox' id='' name='ckboxes[]' value='green'/>
<input type='checkbox' id='' name='ckboxes[]' value='red'/>
<input type='checkbox' id='' name='ckboxes[]' value='blue'/>

同样不引用数字，引号内的内容被视为string

因此，$check['1']应为$check[1]。

检查值不插入数据库 - PHP

1 个答案: