Question

当我尝试在csv文件中填充用户First_Name时，我收到此错误。有人能告诉我我做错了吗

 import csv

# Define users 
valid_input = False
while not valid_input:
    users =raw_input('Number of users: ')
    try:
        users = range(0,int(users))
        valid_input = True
    except:
        print "Invalid input"
        pass

First_Name = ["Test"+str(user) for user in  range (1, users+1)]
Last_Name = ["User%s" %user for user in users]
Email_Addresses = []
for user in users:
    email= raw_input("Email domain for user %d: " %user)
    Email_Addresses.append(Last_Name[user] + email)
Password = ["Password1" for user in users]
Group =["Test" for user in users]
Admin = ["Yes" for user in users]
# open a file for writing.
# open a file for writing.
with open('users.csv', 'wb') as csv_out:
    writer = csv.writer(csv_out)
    writer.writerows(zip(Email_Addresses, Password, First_Name, Last_Name, Group, Admin))

这是我得到的回溯 Traceback（最近一次调用最后一次）： First_Name = [“测试”+ str（用户）范围内的用户（1，用户+ 1）] TypeError：只能将列表（不是“int”）连接到列表

Answer 1

users是一个列表：

users = range(0,int(users))

但是您尝试从该列表中创建 new 范围：

First_Name = ["Test"+str(user) for user in  range (1, users+1)]

其中users + 1是尝试将1添加到列表中。

不要那样做。只需循环现有范围：

First_Name = ["Test"+str(user + 1) for user in users]

错误：只能将列表（不是“int”）连接到列表

1 个答案: