Question

我习惯在mysql中使用嵌套集并检索我通常会使用以下内容的单个路径：

SELECT node.treeID,
       node.name,
       node.lft,
       node.rgt,
       (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM docsTree AS node,
     docsTree AS parent,
     docsTree AS sub_parent,

  ( SELECT node.name,
           (COUNT(parent.name) - 1) AS depth
   FROM docsTree AS node,
        docsTree AS parent
   WHERE node.lft BETWEEN parent.lft AND parent.rgt
     AND node.treeID = :requestedNode
   GROUP BY node.treeID,
            node.name,
            node.lft,
            node.rgt
   ORDER BY node.lft)AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
  AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
  AND sub_parent.name = sub_tree.name
GROUP BY node.treeID,
         node.name,
         node.lft,
         node.rgt HAVING depth = 1
ORDER BY node.lft

现在我需要在db2中执行相同操作，但上面的查询给出了以下错误：

错误：SELECT或HAVING子句中的列引用无效，因为它不是分组列;或列引用在GROUP BY子句中无效。

[SQL0122]专栏 SELECT列表中的DEPTH或表达式无效。错误代码：-122

如何从db2返回嵌套的设置路径？

Answer 1

在最后一组中，尝试使用

GROUP BY node.treeID,
     node.name,
     node.lft,
     node.rgt HAVING (COUNT(parent.name) - (sub_tree.depth + 1)) = 1

嵌套set db2检索单个路径

1 个答案: