这是我的代码
$this->db->select('*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id', FALSE);
错误: 遇到错误
Unknown column '1' in 'field list'
请帮帮我!!!
答案 0 :(得分:0)
似乎您忘了指定您的表名。
请将[tablename]替换为您的表格名称:
$this->db->query('SELECT *, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id FROM [tablename]');
或:
$this->db->select("*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id");
$this->db->from("[tablename]");
$res = $this->db->get();
答案 1 :(得分:0)
试试这种方式
$this->db->select("*, CONCAT(left(card_id, 1 ), right(card_id, 6 )) AS character_id",FALSE);
$this->db->from("table");
$query = $this->db->get();
return $query;