以下行提出了问题
content = new StreamReader(new GZipStream(new MemoryStream(a.RawBytes), CompressionMode.Decompress)).ReadToEnd();
发生InvalidDataException:GZip标头中的幻数不是 正确。确保您使用的是GZip流。
我可以不将附件转换为字节数组或者我做错了什么?
Attachment a = (from x in mail.Attachments.OfType<Attachment>()
where !string.IsNullOrEmpty(x.Body) || x.RawBytes != null
select x).FirstOrDefault();
AttachmentName = a.Name;
string AttachmentType = a.Name.Substring(a.Name.Length - 3, 3).ToUpper();
switch (AttachmentType)
{
case "ZIP":
content = new StreamReader(new GZipStream(new MemoryStream(a.RawBytes), CompressionMode.Decompress)).ReadToEnd();
break;
default:
content = new StreamReader(new MemoryStream(a.RawBytes)).ReadToEnd();
break;
}
答案 0 :(得分:4)
GZip文件与Zip文件不同。您需要System.IO.Compression.ZipFile或ZipArchive。