使用MySQL的PHP​​搜索引擎：无法使用多个关键字进行搜索，会产生PDOException错误

Question

对于php和mysql，我必须说我还是个孩子，但我每天都在学习和改进你们的帮助。 是的，我使用MySQL在PHP中创建了一个搜索引擎，并且在某种程度上，它正在运行，但我遇到的挑战是当我使用多个关键字搜索“David Smith”时出现PDOException错误消息但只有'大卫'或'史密斯'，我没有任何错误。

老实说，我不知道在哪里弄错了。我使用wampserver PDO db connection作为我的数据库。下面是代码示例。

    //search button name and id is 'search'

    $search_exploded = explode (" ", $search);

    foreach($search_exploded as $search_each)
        {
            for($x=0; $x<=0; $x++ ); 

            if($x==1)
                $construct .="UserID LIKE '%$search_each%' or Requestor LIKE '%$search_each%' or EmploymentType LIKE '%$search_each%'";
            else
                $construct .="AND UserID LIKE '%$search_each%' AND Requestor LIKE '%$search_each%' AND EmploymentType LIKE '%$search_each%'"; 
        }
    $sql = "SELECT COUNT(*) as num FROM ".TBL_STUDENTS." WHERE $construct";
    $result = $database->connection->prepare($sql);
    $result->execute(array($construct)); 

就像我说的那样，当我使用像“大卫”这样的单个关键字进行搜索时，它可以正常运行，但当我搜索“David Smith”之类的内容时，我会收到错误。

以下是我收到的错误消息：

Fatal error: Uncaught exception '`PDOException`' with message '`SQLSTATE[42000]`:
Syntax error or access violation: 1064 You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the right syntax
to use near 'UserID LIKE '%Gift%' or Requestor LIKE `%Gift%` or EmploymentType LIKE `%Gift%` at line 3'
in `C:\wamp\www\ccnl\script\search_db.php` on line 108

该行是以下代码

$result->execute(array($construct)); 

Answer 1

尝试使用数组，然后将其插入： -

//search button name and id is 'search'

$search_exploded = explode (" ", $search);

$construct = array();

foreach($search_exploded as $search_each)
{
    $construct[] =" (UserID LIKE '%$search_each%' or Requestor LIKE '%$search_each%' or EmploymentType LIKE '%$search_each%') ";
}
$sql = "SELECT COUNT(*) as num FROM ".TBL_STUDENTS." WHERE ".implode(" OR ", $construct);
$result = $database->connection->prepare($sql);
$result->execute(array($construct));

Answer 2

放一个空格

$construct .="AND Use

在和之前面对这样：

$construct .=" AND Use