Question

我想将两个变量的值从Java applet发送到PHP文件中），我尝试了以下代码。

try {
URL url = new URL(getCodeBase(),"abc.php");
URLConnection con = url.openConnection();

con.setDoOutput(true);
PrintStream ps = new PrintStream(con.getOutputStream());

ps.print("score="+score);
ps.print("username="+username);

con.getInputStream();

ps.close();
} catch (Exception e) {
   g.drawString(""+e, 200,100);
}

我收到以下错误：

java.net.UnknownServiceException:protocol doesn't support output

Answer 1

java.net.UnknownServiceException:protocol doesn't support output

表示您使用的是不支持输出的协议。

getCodeBase()指的是文件网址，如

file:/path/to/the/applet

协议为file，不支持outout。您正在寻找支持输出的http协议。

也许你想要getDocumentBase()，它实际上会返回applet所在的网页，即

http://www.path.to/the/applet

Answer 2

这是我在自己的applet中使用的一些代码，用于将值（通过POST）发送到我服务器上的PHP脚本：

我会像这样使用它：

String content = "";
   content = content + "a=update&gid=" + gid + "&map=" + getMapString();
   content = content + "&left_to_deploy=" + leftToDeploy + "&playerColor=" + playerColor;
   content = content + "&uid=" + uid + "&player_won=" + didWin;
   content = content + "&last_action=" + lastActionCode + "&appletID=" + appletID;

   String result = "";
   try {
    result = requestFromDB(content);
    System.out.println("Sending - " + content);
   } catch (Exception e) {
     status = e.toString();
   }

正如您所看到的，我将所有值加起来发送到“content”字符串，然后调用我的requestFromDB方法（发布我的“请求”值，并返回服务器的响应）：

  public String requestFromDB(String request) throws Exception
  {
    // This will accept a formatted request string, send it to the
    // PHP script, then collect the response and return it as a String.
    URL                 url;
    URLConnection   urlConn;
    DataOutputStream    printout;
    DataInputStream     input;
    // URL of CGI-Bin script.      
     url = new URL ("http://" + siteRoot + "/globalconquest/applet-update.php");

    // URL connection channel.
    urlConn = url.openConnection();
    // Let the run-time system (RTS) know that we want input.
    urlConn.setDoInput (true);
    // Let the RTS know that we want to do output.
    urlConn.setDoOutput (true);
    // No caching, we want the real thing.
    urlConn.setUseCaches (false);
    // Specify the content type.
    urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
    // Send POST output.
    printout = new DataOutputStream (urlConn.getOutputStream ());
    printout.writeBytes (request);
    printout.flush ();
    printout.close ();
    // Get response data.
    input = new DataInputStream (urlConn.getInputStream ());
    String str;
   String a = "";
    while (null != ((str = input.readLine())))
    {
      a = a + str;
    }

    input.close ();
    System.out.println("Got " + a);
    if (a.trim().equals("1")) {
       // Error!
       mode = "error";
    }

   return a;

  } // requestFromDB

在我的PHP脚本中，我只需要查看$ _POST我的值。然后我会打印一个回复。

注意！出于安全原因，您的PHP脚本必须与applet位于同一服务器上，否则无效。

将值从applet传递给PHP

2 个答案: