我正在尝试分析字符串的内容。如果在单词中混合了标点符号,我想用空格替换它们。
例如,如果Johnny.Appleseed!是:a * good& farmer作为输入输入,则应该说有6个单词,但我的代码只将其视为0个单词。我不确定如何删除不正确的字符。
仅供参考:我正在使用python 3,我也无法导入任何库
string = input("type something")
stringss = string.split()
for c in range(len(stringss)):
for d in stringss[c]:
if(stringss[c][d].isalnum != True):
#something that removes stringss[c][d]
total+=1
print("words: "+ str(total))
答案 0 :(得分:15)
strs = "Johnny.Appleseed!is:a*good&farmer"
lis = []
for c in strs:
if c.isalnum() or c.isspace():
lis.append(c)
else:
lis.append(' ')
new_strs = "".join(lis)
print new_strs #print 'Johnny Appleseed is a good farmer'
new_strs.split() #prints ['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']
使用regex
:
>>> import re
>>> from string import punctuation
>>> strs = "Johnny.Appleseed!is:a*good&farmer"
>>> r = re.compile(r'[{}]'.format(punctuation))
>>> new_strs = r.sub(' ',strs)
>>> len(new_strs.split())
6
#using `re.split`:
>>> strs = "Johnny.Appleseed!is:a*good&farmer"
>>> re.split(r'[^0-9A-Za-z]+',strs)
['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']
答案 1 :(得分:11)
这是一个不需要导入任何库的单行解决方案
它用空格替换非字母数字字符(如标点符号),然后split
为字符串。
灵感来自“Python strings split with multiple separators”
>>> s = 'Johnny.Appleseed!is:a*good&farmer'
>>> words = ''.join(c if c.isalnum() else ' ' for c in s).split()
>>> words
['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']
>>> len(words)
6
答案 2 :(得分:3)
试试这个:它使用re解析word_list,然后创建word:appearances
字典import re
word_list = re.findall(r"[\w']+", string)
print {word:word_list.count(word) for word in word_list}
答案 3 :(得分:2)
如何使用收藏品中的Counter?
import re
from collections import Counter
words = re.findall(r'\w+', string)
print (Counter(words))
答案 4 :(得分:1)
for ltr in ('!', '.', ...) # insert rest of punctuation
stringss = strings.replace(ltr, ' ')
return len(stringss.split(' '))
答案 5 :(得分:1)
我知道这是一个古老的问题但......这个怎么样?
string = "If Johnny.Appleseed!is:a*good&farmer"
a = ["*",":",".","!",",","&"," "]
new_string = ""
for i in string:
if i not in a:
new_string += i
else:
new_string = new_string + " "
print(len(new_string.split(" ")))
答案 6 :(得分:0)
#Write a python script to count words in a given string.
s=str(input("Enter a string: "))
words=s.split()
count=0
for word in words:
count+=1
print(f"total number of words in the string is : {count}")