我创建了一个这样的多对多数据库:
CREATE TABLE Films (
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
Title VARCHAR(255));
CREATE TABLE Ambiences (
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
ambienceName VARCHAR(255));
CREATE TABLE Films_Ambiences (
film_id INT NOT NULL,
ambience_id INT NOT NULL,
PRIMARY KEY (film_id, ambience_id),
FOREIGN KEY (film_id) REFERENCES Films(id) ON UPDATE CASCADE,
FOREIGN KEY (ambience_id) REFERENCES Ambiences(id) ON UPDATE CASCADE);
现在:我已插入一些数据并加入表格以获取:
╔════════╦════╦══════════╗
║ Title ║ id ║ Ambience ║
╠════════╬════╬══════════╣
║ film_1 ║ 1 ║ Funny ║
║ film_1 ║ 1 ║ Sad ║
║ film_2 ║ 2 ║ Funny ║
║ film_2 ║ 2 ║ Sad ║
╚════════╩════╩══════════╝
但是,我的目标是在一行中显示film_1,在第二行中显示film_2,如下所示:
╔════════╦════╦══════════╗
║ Title ║ id ║ Ambience ║
╠════════╬════╬══════════╣
║ film_1 ║ 1 ║ Funny,Sad║
║ film_2 ║ 2 ║ Funny,Sad║
╚════════╩════╩══════════╝
我正在尝试使用GROUP_CONCAT
,但我得到了:
╔════════╦════╦════════════════════════╗
║ Title ║ id ║ Ambience ║
╠════════╬════╬════════════════════════╣
║ film_1 ║ 1 ║ funny, funny, sad, sad ║
╚════════╩════╩════════════════════════╝
它将所有行合并为一个行。 这是 SQLFiddle 。
答案 0 :(得分:2)
您需要添加GROUP BY
:
SELECT title,
GROUP_CONCAT(ambienceName SEPARATOR ' ') AS ambiences
FROM Films AS f
INNER JOIN Films_Ambiences as fa
ON f.id = fa.film_id
INNER JOIN Ambiences AS a
ON a.id = fa.ambience_id
GROUP BY title
结果是:
TITLE AMBIENCES
film1 sad happy
film2 sad happy