你好,我正在开发一个Android应用程序,我试图上传一个文件到我的ftp服务器与Url连接连接成功,但它不上传文件到我的服务器和logcat也没有显示任何错误这是我的代码任何帮助将提前appriciated thanx。 {仅限主要代码}
代码:
new Thread(new Runnable() {
@Override
public void run() {
String host = "ethicstrain.tk";
String user = "myuername";
String pass = "mypass";
String filePath = Environment.getExternalStorageDirectory()+"/index2.html";
String uploadPath = "public_html/"+str+"/index.html";
String filename = "index2.html";
StringBuffer sb = new StringBuffer( "http://" );
sb.append( user );
sb.append( ':' );
sb.append( pass);
sb.append( '@' );
sb.append( host );
sb.append( '/' );
sb.append( str ); // str is the text input from EditText.
sb.append( '/');
sb.append(filename);
sb.append( ";type=i" );
BufferedInputStream bis = null;
BufferedOutputStream bos = null;
try
{
URL url = new URL(sb.toString());
URLConnection urlc = url.openConnection();
if(true){
Log.v ("connecting to server", filename);
}
urlc.setDoOutput(true);
bos = new BufferedOutputStream( urlc.getOutputStream() );
bis = new BufferedInputStream( new FileInputStream(filePath ) );
int i;
while ((i = bis.read()) != -1)
{
bos.write( i );
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
if (bis != null)
try
{
Log.v("","file uploaded to server");
bis.close();
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
if (bos != null)
try
{
bos.close();
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
}
}
/
}).start();
现在我正在使用apache ftpclient,这不显示任何错误,但文件未上传 这里是代码
try{
FTPClient client = new FTPClient ();
client.connect(server);
client.enterLocalPassiveMode();
client.login(user, pass);
client.makeDirectory("/public_html/"+str);
client.changeWorkingDirectory(str);
@SuppressWarnings("unused")
String ac = "30073761354";
client.setFileType(FTP.BINARY_FILE_TYPE);
client.setFileTransferMode(FTP.BINARY_FILE_TYPE );
FileInputStream is = null;
is = new FileInputStream(Environment.getExternalStorageDirectory()+"/index.html");
Boolean isStored = client.storeFile("/public_html/"+str+"/", is);
is.close();
client.logout();
client.disconnect();
}