此问题与node-mysql有关。
我似乎遇到了以下代码的问题,而且似乎与使用用户定义的变量有关。渲染的查询在任何mysql IDE中运行良好,返回多个记录。但是当由node-mysql执行时,它只返回一条记录。
我已经验证,消除指定T3.gender_rank的WHERE子句会在node-mysql和我的mysql IDE中创建可预测的结果。
之前是否提出过这个问题,还是我做错了?
var mysql = require('mysql'); // Establish SQL Support
var sql =
"select team, `div`, sum(points) AS teampoints "+
"from ( "+
" select "+
" *, "+
" (@genderRank := CASE WHEN @genderTMP <> gender THEN 1 ELSE @genderRank+1 END) AS gender_rank, "+
" (@genderTMP := gender) AS _gt "+
" from ( "+
" select * "+
" from racepoints "+
" WHERE "+
" ltrim(rtrim(race)) = '"+data.eventName+"' AND "+
" racedate = '"+getSimpleDate(new Date(data.eventStart))+"' "+
" ORDER BY team,gender,points DESC "+
" ) T1, "+
" (select @genderRank:=0 AS gender_rank_start) T2 "+
") T3 "+
"WHERE "+
" (T3.gender_rank <= 4 AND rtrim(ltrim(`div`)) = 'D2') OR "+
" (T3.gender_rank <= 3 AND rtrim(ltrim(`div`)) = 'D1') "+
"GROUP BY team, `div` "+
"ORDER BY `div`, teampoints DESC, team";
var db = new mysql.createConnection({
host : 'localhost',
user : 'root',
password : 'admin',
database : 'nps',
multipleResults : true
});
db.connect();
db.query(
sql,
function(err,rows,fields){
if(err){
console.log(err);
return;
}
console.log(rows);
}
);
db.end();
SQL数据库文件也可在此处获取:https://snipt.net/download/dde8b4b5ce8cd5fca21ac2334bae634f/-5369.sql
答案 0 :(得分:1)
不要直接将变量添加到sql字符串中,而是让mysql包为您完成。这通常可以解决像这样的问题,并且还可以防止SQL注入。
这是使用问号(每个变量一个)后跟一组变量来完成的。
例如
connection.query('SELECT * FROM users WHERE id = ?', [userId], function(err, results) {
// ...
});