Question

我想从Queue.Queue或TCP套接字中读取消息，以先到者为准。如果不诉诸2个线程怎么能实现呢？平台是Windows上的CPython 2.7.5

Answer 1

有一个非常好的技巧可以解决您的问题{/ 3}}。

{{1}}

Answer 2

要在单个线程中执行此操作，您必须使用非阻塞方法，并将它们合并到单个事件循环中。我实际上在这里使用select而不是非阻塞套接字I / O，因为如果你需要从多个套接字读取它会更清晰......

import socket
import select
import Queue
import time

TIMEOUT = 0.1   # 100ms


def process_queue_item(item):
    print 'Got queue item: %r' % item


def process_socket_data(data):
    print 'Got socket data: %r' % data


def main():

    # Build queue
    queue = Queue.Queue()
    for i in range(10):
        queue.put(i)
    queue.put(None)   # Using None to indicate no more data on queue
    queue_active = True

    # Build socket
    sock = socket.socket()
    sock.connect(('www.google.com', 80))
    sock.send('GET / HTTP/1.0\r\n\r\n')
    socket_active = True

    # Main event loop
    while 1:

        # If there's nothing to read, bail out
        if not (socket_active or queue_active):
            break

        # By default, sleep at the end of the loop
        do_sleep = True

        # Get data from socket without blocking if possible
        if socket_active:
            r, w, x = select.select([sock], [], [], TIMEOUT)
            if r:
                data = sock.recv(64)
                if not data:    # Hit EOF
                    socket_active = False
                else:
                    do_sleep = False
                    process_socket_data(data)

        # Get item from queue without blocking if possible
        if queue_active:
            try:
                item = queue.get_nowait()
                if item is None:  # Hit end of queue
                    queue_active = False
                else:
                    do_sleep = False
                    process_queue_item(item)
            except Queue.Empty:
                pass

        # If we didn't get anything on this loop, sleep for a bit so we
        # don't max out CPU time
        if do_sleep:
            time.sleep(TIMEOUT)


if __name__ == '__main__':
    main()

输出看起来像......

Got socket data: 'HTTP/1.0 302 Found\r\nLocation: http://www.google.co.uk/\r\nCache-Co'
Got queue item: 0
Got socket data: 'ntrol: private\r\nContent-Type: text/html; charset=UTF-8\r\nSet-Cook'
Got queue item: 1
Got socket data: 'ie: PREF=ID=a192ab09b4c13176:FF=0:TM=1373055330:LM=1373055330:S='
Got queue item: 2
etc.

Answer 3

你可以按照以下方式做点什么：

def check_for_message(queue,socket,sock_accept_size=512):
    socket.setblocking(0)
    while True:
        try:
            sock_msg=socket.recv(sock_accept_size)
        except socket.error:
            """Do stuff if there is no message"""
            sock_msg=None
        try:
            que_msg=queue.get()
        except Queue.Empty:
            """Do stuff if there is no message"""
            que_msg=None
        yield (que_msg,sock_msg)

然后你可以使用：

迭代它

for que_message,sock_message in check_for_message(que_instance,socket_instance):
    print que_message,sock_message

Python - 如何在同一时间等待队列和套接字

3 个答案: