请在这个AS3和Java代码中需要你的帮助。该程序 用于将图片从flex应用程序上传到远程服务器。该 代码效果很好，但我需要添加一些东西，我正在寻找一种方法 发送和额外的参数以及图像。让我们说我想 发送上传图片的人的用户名和 图片。请问如何使用AS3从客户端发送它以及如何发送 我收到servlet上的数据。
这是AS3代码
private var fileRef:FileReference = new FileReference();
private var servletTarget:URLRequest = new URLRequest(urlpath+"Comeboard/UploadImage");
private function fileBrowse():void
{
fileRef.addEventListener(Event.SELECT, onSelect);
fileRef.addEventListener(ProgressEvent.PROGRESS,progressHandler);
//just a label
uploadStatus.text = "Browsing the File System";
//a text field
fileLocation.text = "";
fileRef.browse();
}
private function onSelect(event:Event):void
{
uploadStatus.text = "File selected";
fileLocation.text = fileRef.name;
}
private function progressHandler(event:ProgressEvent):void
{
uploadStatus.text = "The file is " + percentLoaded + "% loaded";
}
private function fileUpload():void
{
//assuming this is the data i want to send
var data:String = "webdezzi";
uploadStatus.text = "Uploading....";
var menuURLVars:URLVariables = new URLVariables();
servletTarget.method = URLRequestMethod.POST;
fileRef.upload(servletTarget);
}
这是Servlet上的代码。请注意多行注释。 提前谢谢。
// Import required java libraries
import java.awt.Graphics2D;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import java.util.Iterator;
import java.util.List;
import javax.imageio.ImageIO;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
public class UploadImage extends HttpServlet {
String boardname = null;
private boolean isMultipart;
private String filePath;
private int maxFileSize = 1000 * 1024;
private int maxMemSize = 4 * 1024;
private File file ;
private static final long serialVersionUID = 1L;
public void init( )
{
// Get the file location where it would be stored.
filePath =
getServletContext().getRealPath("/");
}
public void doPost(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, java.io.IOException
{
// Check that we have a file upload request
isMultipart = ServletFileUpload.isMultipartContent(request);
response.setContentType("text/html");
java.io.PrintWriter out = response.getWriter( );
if( !isMultipart )
{
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
out.println("<p>No file uploaded</p>");
out.println("</body>");
out.println("</html>");
return;
}
DiskFileItemFactory factory = new DiskFileItemFactory();
// maximum size that will be stored in memory
factory.setSizeThreshold(maxMemSize);
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
// maximum file size to be uploaded.
upload.setSizeMax( maxFileSize );
try{
// Parse the request to get file items.
List fileItems = upload.parseRequest(request);
// Process the uploaded file items
Iterator i = fileItems.iterator();
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
while ( i.hasNext () )
{
FileItem fi = (FileItem)i.next();
System.out.println("kkkkkkkk"+fi.getFieldName());
if (fi.isFormField())
{
/*****************************************************
* i beleive this is where i am supposed to
* process the data i receive.
* i might be wrong though, *
******************************************************/
processFormField(fi);
}
if ( !fi.isFormField () )
{
processUploadedFile(fi);
}
}
out.println("</body>");
out.println("</html>");
}
catch(Exception ex)
{
out.println(ex.getMessage());
}
}
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, java.io.IOException
{
throw new ServletException("GET method used with " +
getClass( ).getName( )+": POST method required.");
}
private void processFormField(FileItem item)
{
String name = item.getFieldName();
String value = item.getString();
System.out.println("Item name: " + name + " ; value: " + value);
}
private void processUploadedFile(FileItem item) throws Exception
{
String fieldName = item.getFieldName();
String fileName = item.getName();
String contentType = item.getContentType();
boolean isInMemory = item.isInMemory();
long sizeInBytes = item.getSize();
boolean writeToFile = true;
if (sizeInBytes > (5 * 1024 * 1024))
{
writeToFile = false;
}
// Process a file upload
if (writeToFile)
{
//File uploadedFile = new File(filePath + fileName);
File uploadedFile = new File(filePath + boardname);
if (!uploadedFile.exists())
{
uploadedFile.createNewFile();
}
item.write(uploadedFile);
}
else
{
System.out.println("Trying to write a large file.");
}
}
}
答案 0 :(得分：0)
你问题的flash部分怎么样：
标准AS3 FileReference不允许向多部分请求添加自定义参数，但您可以自己构建多部分请求并通过URLLoader发送。
以下是多部分请求创建的代码：
private static const BOUNDARY:String = "boundary";
public static function createMultiPartRequest(url:String, bytes:ByteArray, fileProp:String="file1", fileName:String="file1.png", params:Object=null):URLRequest
{
var request:URLRequest = new URLRequest(url);
var header1:String = "\r\n--" + BOUNDARY + "\r\n" +
"Content-Disposition: form-data; name=\""+fileProp+"\"; filename=\""+fileName+"\"\r\n" +
"Content-Type: image/png\r\n" + "\r\n";
var headerBytes1:ByteArray = new ByteArray();
headerBytes1.writeMultiByte(header1, "ascii");
var postData:ByteArray = new ByteArray();
postData.writeBytes(headerBytes1, 0, headerBytes1.length);
if(bytes)
postData.writeBytes(bytes, 0, bytes.length);
if (!params)
params = {};
if (!params.Upload)
params.Upload = "Submit Query";
for (var prop:String in params) {
var header:String = "--" + BOUNDARY + "\r\n" + "Content-Disposition: form-data; name=\""+prop+"\"\r\n" + "\r\n" + params[prop]+"\r\n" + "--" + BOUNDARY + "--";
var headerBytes:ByteArray = new ByteArray();
headerBytes.writeMultiByte(header, "ascii");
postData.writeBytes(headerBytes, 0, headerBytes.length);
}
request.data = postData;
request.method = URLRequestMethod.POST;
request.contentType = "multipart/form-data; boundary=" + BOUNDARY;
return request;
}
用法（使用fileUpload()方法代替标准fileRef.upload()）：
var image:ByteArray = fileRef.data;
var request:URLRequest = createMultiPartRequest("test.com", image, "file1", "file1.png", {param1:value1});
var loader:URLLoader = new URLLoader();
loader.load(request);
答案 1 :(得分：0)
Sotirios Delimanolis的建议帮助解决了这个问题，但我仍会尝试其他建议。
在AS3中
var header:URLRequestHeader = new URLRequestHeader("username", username);
servletTarget.requestHeaders.push(header);
在Servlet中
String username = request.getHeader("username");