Question

目前，我使用exec / wget来回调URL而不阻止PHP脚本：

$newURL = /* URL we need to callback */
$newURL = escapeshellarg($newURL);
exec("curl -k $newURL > /dev/null &");

我想获得回调URL的响应并测试它是否以完全指定的字符串响应。但是，它不能阻止执行脚本的其余部分。

我怎样才能做到这一点？

Answer 1

This post有一个使用分叉卷曲请求发送aysnc请求的解决方案：

private function request($url, $payload) {

  $cmd = "curl -X POST -H 'Content-Type: application/json'";
  $cmd.= " -d '" . $payload . "' " . "'" . $url . "'";

  if (!$this->debug()) {
    $cmd .= " > /dev/null 2>&1 &";
  }

  exec($cmd, $output, $exit);
  return $exit == 0;
}

它还有一个解决方案，你可以在关闭它之前写入套接字（在你得到响应之前）：

private function request($body) {

    $protocol = "ssl";
    $host = "api.segment.io";
    $port = 443;
    $path = "/v1/" . $body;
    $timeout = $this->options['timeout'];

    try {
      # Open our socket to the API Server.
      $socket = fsockopen($protocol . "://" . $host, $port,
                          $errno, $errstr, $timeout);

      # Create the request body, and make the request.
      $req = $this->create_body($host, $path, $content);
      fwrite($socket, $req);
      # ...
    } catch (Exception $e) {
      # ...
    }
}

PHP：访问URL async并获得响应而不会阻止

1 个答案: