我必须在画布上绘制3张图像,并需要旋转2张图像。
图像就像 1.圆形,垂直直线 2.只是一条水平线 3.大圆形图像
我需要在画布中心旋转前2个图像。
var canvas = document.getElementById('NewImage');
var context = canvas.getContext('2d');
context.canvas.width = window.innerWidth;
context.canvas.height = window.innerHeight*0.7;
var imageObj = new Image();
var imageObj2 = new Image();
var imageObj3 = new Image();
imageObj.onload = function() {
context.save();
context.translate(imageObj.width/2,imageObj.height/2);
context.rotate(-10*Math.PI/180);
//context.translate(-imageObj.width/2,-imageObj.height/2);
context.drawImage(imageObj,-(imageObj.width/2),-(imageObj.height/2),context.canvas.width,context.canvas.height*0.85);
context.restore();
context.save();
context.globalCompositeOperation="source-over";
context.translate(imageObj2.width/2,imageObj2.height/2);
context.rotate(-10*Math.PI/180);
context.translate(-imageObj2.width/2,-imageObj2.height/2);
context.drawImage(imageObj2, x, y,context.canvas.width,6);
context.restore();
//context.rotate(10*Math.PI/180);
context.drawImage(imageObj3, 0, 0,context.canvas.width,context.canvas.height*0.9);
};
imageObj.src = 'canvas/inner_circle_blackline_vertical.png';
imageObj2.src = 'canvas/horizontal.png';
imageObj3.src = 'canvas/outer_circle.png';
当我尝试旋转时,图像不会在中心旋转。当第1张图像旋转时,它必须看起来像“X”符号。
我将如何在画布的中心旋转。
感谢:)
答案 0 :(得分:2)
按照设计,您的imageObj2和imageObj3永远不会加载。
这是一个通用的图像加载器,它将加载所有图像并将它们存储在名为imgs []的数组中。
当所有图像都已完全加载时,将调用render()函数。这就是你开始画画的地方。
// This is an image loader
// When render() is called, all your images are fully loaded
var imgURLs = [
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png",
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png",
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png"];
var imgs=[];
var imgCount=0;
pre_load();
function pre_load(){
for(var i=0;i<imgURLs.length;i++){
var img=new Image();
imgs.push(img);
img.onload=function(){
if(++imgCount>=imgs.length){
// images are now fully loaded
render();
}
}
img.src=imgURLs[i];
}
}
在render()中,您只需绘制图像。
由于重复执行相同的操作(旋转图像),您可以创建辅助函数来执行旋转绘图。这里的辅助函数是drawImageAtAngle。
// draw the rotated lines on the canvas
function render(){
var x=canvas.width/2;
var y=canvas.height/2;
drawImageAtAngle(imgs[0],x,y,-45);
drawImageAtAngle(imgs[2],x,y,45);
drawImageAtAngle(imgs[1],x,y,0);
}
这里是将提供的图像旋转到提供角度的辅助函数:
function drawImageAtAngle(image,X,Y,degrees){
var radians=degrees*Math.PI/180;
var halfWidth=image.width/2;
var halfHeight=image.height/2;
ctx.beginPath();
ctx.save();
ctx.translate(X,Y);
ctx.rotate(radians);
ctx.drawImage(image,-halfWidth,-halfHeight);
ctx.restore();
}
这是代码和小提琴:http://jsfiddle.net/m1erickson/ZShWW/
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" media="all" href="css/reset.css" /> <!-- reset css -->
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<style>
body{ background-color: ivory; padding:10px;}
canvas{border:1px solid red;}
</style>
<script>
$(function(){
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
// This is an image loader
// When render() is called, all your images are fully loaded
var imgURLs = [
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png",
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png",
"https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png"];
var imgs=[];
var imgCount=0;
pre_load();
function pre_load(){
for(var i=0;i<imgURLs.length;i++){
var img=new Image();
imgs.push(img);
img.onload=function(){
if(++imgCount>=imgs.length){
// images are now fully loaded
render();
}
}
img.src=imgURLs[i];
}
}
// draw the rotated lines on the canvas
function render(){
var x=canvas.width/2;
var y=canvas.height/2;
drawImageAtAngle(imgs[0],x,y,-45);
drawImageAtAngle(imgs[2],x,y,45);
drawImageAtAngle(imgs[1],x,y,0);
}
function drawImageAtAngle(image,X,Y,degrees){
var radians=degrees*Math.PI/180;
var halfWidth=image.width/2;
var halfHeight=image.height/2;
ctx.beginPath();
ctx.save();
ctx.translate(X,Y);
ctx.rotate(radians);
ctx.drawImage(image,-halfWidth,-halfHeight);
ctx.restore();
}
}); // end $(function(){});
</script>
</head>
<body>
<p>This is the line image</p>
<img src="https://dl.dropboxusercontent.com/u/139992952/stackoverflow/line.png">
<p>The line image rotated at center of canvas</p>
<canvas id="canvas" width=300 height=300></canvas>
</body>
</html>
答案 1 :(得分:0)
要查找画布的中心,您必须使用画布的尺寸。在您的代码中,您使用的是图像的尺寸。也就是说,这一行:
context.translate(imageObj.width/2,imageObj.height/2);
应该是:
context.translate(canvas.width/2,canvas.height/2);
将您移动到画布的中心。然后围绕该中心发生旋转。然后,您将以原点为中心绘制图像。那部分看起来是正确的。
然后,您将反转旋转,然后翻译。