从表中获取完全匹配记录

Question

我的表有两列trial_id，category_id

我正在附加图像以使其更清晰。

我想要具有category_id 260,2880的trial_id记录。

好的，我可以使用“in”语句

运行查询

某事“SELECT * FROM trial_category WHERE category_id IN（260,2880）”

它将trial_id设为73,213，但73还有很多其他类别。所以这不应该显示在结果中。

结果应该只包含213个trial_id，或者我在213中添加另一个category_id，然后213不应该显示。

由于

Answer 1

如果我说得对，你只需要只包含260或2880的trial_id（两者都是？）

SELECT * 
   FROM trial_category 
   WHERE category_id IN (260, 2880)
   and trial_id NOT IN (select trial_id 
                         from trial_category 
                         where category_id NOT IN (260, 2880))

Answer 2

试试这个：

SELECT 
    * 
FROM 
    trial_category 
WHERE 
    category_id IN ( 260, 2880 ) 
    AND trial_id=213

这将只为这两个类别提供trial_id：

SELECT 
    trial_id 
FROM 
    trial_category 
GROUP BY
    trial_id
HAVING
    GROUP_CONCAT( DISTINCT category_id ORDER BY category_id) = '260,2880'

Answer 3

 SELECT x.* 
   FROM trial_category x
   LEFT
   JOIN trial_category y
     ON y.trial_id = x.trial_id
    AND y.category_id NOT IN(260,2880)
  WHERE x.category_id IN (260,2880)
    AND y.id IS NULL;