Question

如何在Julia中从正在运行的脚本请求用户输入？在MATLAB中，我会这样做：

result = input(prompt)

由于

Answer 1

最简单的事情是readline(stdin)。这就是你要找的东西吗？

Answer 2

正如@StefanKarpinski指出的那样，未来将会解决这个问题，这就是我现在所做的事情：

julia> @doc """
           input(prompt::String="")::String

       Read a string from STDIN. The trailing newline is stripped.

       The prompt string, if given, is printed to standard output without a
       trailing newline before reading input.
       """ ->
       function input(prompt::String="")::String
           print(prompt)
           return chomp(readline())
       end
input (generic function with 2 methods)

julia> x = parse(Int, input());
42

julia> typeof(ans)
Int64

julia> name = input("What is your name? ");
What is your name? Ismael

julia> typeof(name)
String

help?> input
search: input

  input(prompt::String="")::String

  Read a string from STDIN. The trailing newline is stripped.

  The prompt string, if given, is printed to standard output without a trailing newline before reading input.

julia>

Answer 3

现在在 Julia 1.6.1 中，就像输入一样简单：

num = readline()

是的！没有任何参数，因为readline() 函数的 IO 位置参数的默认值是“stdin”。因此，在上面的示例中，Julia 将读取用户的输入并将其存储在变量“num”中。

Answer 4

检查提供的答案是否与预期的类型匹配的功能：

函数定义：

function getUserInput(T=String,msg="")
  print("$msg ")
  if T == String
      return readline()
  else
    try
      return parse(T,readline())
    catch
     println("Sorry, I could not interpret your answer. Please try again")
     getUserInput(T,msg)
    end
  end
end

函数调用（用法）：

sentence = getUserInput(String,"Write a sentence:");
n        = getUserInput(Int64,"Write a number:");

Answer 5

首先我跑了 Pkg.add（ “日期”）然后

using Dates

println()
print("enter year  "); year = int(readline(STDIN))
print("enter month "); month = int(readline(STDIN))
print("enter day   "); day = int(readline(STDIN))

date = Date(year, month, day)
println(date)

Julia请求脚本中的用户输入

5 个答案: