Question

我想编写一个应用程序，其中主线程启动HTTP服务器，必须等待一个HTTP请求最多10秒。在收到（并处理）请求或超出超时之前，必须阻止应用程序。

我尝试使用此代码：

import BaseHTTPServer

class RequestHandler(BaseHTTPServer.BaseHTTPRequestHandler):
    def do_GET(s):
        s.send_response(200)
        s.send_header("Content-type", "text/html")
        s.end_headers()
        s.wfile.write("<html><head><title>Title</title></head>")

httpd = BaseHTTPServer.HTTPServer(('', 8001), RequestHandler)
httpd.socket.settimeout(10)
httpd.handle_request()

问题是，当服务器收到请求时，我收到以下错误消息：

Exception happened during processing of request from ('127.0.0.1', 51321)
Traceback (most recent call last):
  File "C:\Python27\lib\SocketServer.py", line 284, in _handle_request_noblock
    self.process_request(request, client_address)
  File "C:\Python27\lib\SocketServer.py", line 310, in process_request
    self.finish_request(request, client_address)
  File "C:\Python27\lib\SocketServer.py", line 323, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "C:\Python27\lib\SocketServer.py", line 639, in __init__
    self.handle()
  File "C:\Python27\lib\BaseHTTPServer.py", line 343, in handle
    self.handle_one_request()
  File "C:\Python27\lib\BaseHTTPServer.py", line 313, in handle_one_request
    self.raw_requestline = self.rfile.readline(65537)
  File "C:\Python27\lib\socket.py", line 476, in readline
    data = self._sock.recv(self._rbufsize)
error: [Errno 10035] A non-blocking socket operation could not be completed immediately

如果我删除settimeout函数，我没有收到此错误，但我也失去了超时。我也尝试使用setblocking函数，但它会破坏settimeout的效果。

我如何实现目标？

PS。：我在64位Windows 7上使用Python 2.7.2

使用超时从python处理一个HTTP请求

0 个答案: