我有一个包含以下数据的数据库表:
ID | Date | Bla
1 | 2013-05-01 | 1
2 | 2013-05-02 | 2
3 | 2013-05-03 | 3
4 | 2013-05-05 | 4
请注意,缺少日期:2014-05-04
。我该如何更改以下查询:
SELECT *
FROM table
where DATE >= '2013-05-01' AND DATE <= '2013-05-05'
这样我最终得到以下输出:
ID | Date | Bla
1 | 2013-05-01 | 1
2 | 2013-05-02 | 2
3 | 2013-05-03 | 3
null | 2013-05-04 | null
4 | 2013-05-05 | 4
这可能吗?
答案 0 :(得分:3)
您可以加入generate_series
输出:
select
'2013-05-01'::date + g.o AS "date with offset"
from
generate_series(0, 30) AS g(o)
输出:
"2013-05-01"
"2013-05-02"
"2013-05-03"
...
"2013-05-29"
"2013-05-30"
"2013-05-31"
或者......定义新的存储过程后更简单的方法:)
CREATE OR REPLACE FUNCTION generate_series(date, date) RETURNS
SETOF date AS $$
SELECT $1 + g.s
FROM generate_series(0, ($2 - $1)) AS g(s);
$$ LANGUAGE SQL IMMUTABLE;
就这样称呼它:
SELECT * FROM generate_series(start_date, end_date);
答案 1 :(得分:3)
select *
from
(
select generate_series(
'2013-05-01'::date, '2013-05-05', '1 day'
)::date
) s("date")
left join
t using ("date")
将"date"
替换为实际的列名。
答案 2 :(得分:2)
您需要将表格外部加入“日期列表”:
with all_dates (some_date) as (
select date '2013-05-01' + i
from generate_series(0, 10) i -- adjust here to the range of dates you need.
)
select t.id,
ad.some_date, -- you need to take the actual date from generated ones
t.bla
from all_dates ad
left join the_table t on ad.some_date = t.date
where ad.some_date between date '2013-05-01' and date '2013-05-05';
顺便说一下:date
是一个可怕的名字。除了它是一个保留字之外,它也没有说明什么样的“日期”。