Question

我正在开发一个php项目在线预约表格，它使用多个选择选项列表并隐藏选择选项。

验证失败后，我在选择选项中保留值时遇到问题。

我的选择选项会被触发，就像这个fiddle，

一样

第一个选择选项值将触发第二个选择选项，然后第二个选择选项值将触发一个图像。第一个选择选项值保留，但第二个选择选项值被重置。

我可以保留值，但是当用户想要更改为其他选项时，旧选项的值仍保留在那里，它将附加新值。我想要的是如果用户更改其他选项，它将自动重置为null，但在验证失败后，它会保留。

我在这个jquery中使用了明确的值：

$(document).ready(function(){
  $('#Service').change(function(){    
  $('#selectOp1').prop('selectedIndex',0);
  $('#selectOp2').prop('selectedIndex',0);
  $('#selectOp3').prop('selectedIndex',0);
  $('div.second-level-container').children().hide(); //this one for hide the image
)};

但是当验证失败时，所选值也消失了，这非常令人恼火。有人可以帮助我，我有什么选择，我是jquery的新手

Answer 1

//You can try this this will reset your select box values also 

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script>

<script type="text/javascript">
$(document).ready(function() {
    $('#Rank').bind('change', function() {
        var elements = $('div.container').children().hide(); // hide all the elements
        var value = $(this).val();

        if (value.length) { // if somethings' selected

            elements.filter('.' + value).show(); // show the ones we want

            $('div.container div').children().each(function(){

                $.each(this.attributes, function(i, attrib){

                   if(attrib.name != value)
                   {
                       $('#'+value).prop('selectedIndex',0);
                   }

                  });
             });

            var elements = $('div.second-level-container').children().hide(); // hide all the elements

         //master reset
        }else{

            $('#airman').prop('selectedIndex',0);

            $('#senior-airman').prop('selectedIndex',0);

            var elements = $('div.second-level-container').children().hide();            
        }

    }).trigger('change');

    $('.second-level-select').bind('change', function() {
        var elements = $('div.second-level-container').children().hide(); // hide all the elements
        var value = $(this).val();

        if (value.length) { // if somethings' selected
            elements.filter('.' + value).show(); // show the ones we want

        //reset the child and      
        }else{

            var elements = $('div.second-level-container').children().hide(); // hide all the elements
        }
    }).trigger('change');
});
</script>
<!-- Site JavaScript -->
<select size="1" id="Rank" title="" name="Rank">
    <option value="">-Select Your Rank-</option>
    <option value="airman">Airman</option>
    <option value="senior-airman">Senior Airman</option>
</select>

<div class="container">
    <div class="airman">
        <select class="second-level-select" id='airman'>
            <option value="">-Select Your Rank-</option>
            <option value="basic-ore-1">Basic Ore Miner - Level 1</option>
            <option value="basic-ore-2">Basic Ore Miner - Level 2</option>
        </select>
    </div>
    <div class="senior-airman">
        <select class="second-level-select" id='senior-airman'>
            <option value="">-Select Your Rank-</option>
            <option value="omber-miner-1">Omber Miner - Level 1</option>
            <option value="omber-miner-2">Omber Miner - Level 2</option>
        </select>
    </div>
</div>

<div class="second-level-container">    
    <div class="basic-ore-1">
        Line of text for basic ore miner 1
    </div>
    <div class="basic-ore-2">
        Line of text for basic ore miner 2
    </div>
    <div class="omber-miner-1">
        Line of text for omber miner 1
    </div>
    <div class="omber-miner-2">
        Line of text for omber miner 2
    </div>    
</div>

验证失败后保留值

1 个答案: