Question

我有一个MySQL查询，我正在运行以查明在15分钟的时间间隔内，在任何给定时间（任何指定日期等）为用户预订了多少次呼叫。到目前为止，我有：

    SELECT
date_action,
DATE_FORMAT(date_action, "%i") AS minute,
CASE 
    WHEN minute(date_action) BETWEEN 0 and 14 THEN '00'
    WHEN minute(date_action) BETWEEN 15 and 29 THEN '15'
    WHEN minute(date_action) BETWEEN 30 and 44 THEN '30'
    WHEN minute(date_action) BETWEEN 45 and 59 THEN '45'
END AS intervals
FROM
clients
WHERE
HOUR(date_action) = 09
AND DAY(date_action) = 15
AND MONTH(date_action) = 07
AND YEAR(date_action) = 2013

这很好用，但我缺少的神奇成分是分配给每个区间的调用次数的“计数”，所以例如上面的代码产生：

Date_time - Minute - Interval
2013-07-15 09:54:24 - 54 - 45
2013-07-15 09:29:32 - 29 - 15
2013-07-15 09:13:33 - 13 - 00
2013-07-15 09:53:53 - 53 - 45
2013-07-15 09:00:49 - 00 - 00

所以，我将我的会议记录转换为间隔，因为我只希望每个间隔返回1行，然后在该行间隔附加一个列，其中包含该间隔内呼叫次数的计数，即

Interval - Count
45 - 2
15 - 1
00 - 2

我觉得我已经把头撞在这一块砖墙上太久了，所以任何帮助都会非常感激。虽然在查询之后会进行一些后处理，但如果可能的话，我宁愿在SQL中执行此操作。：）

Answer 1

您可以按间隔进行分组并选择计数。

SELECT
    count(date_action) as count,
    CASE 
        WHEN minute(date_action) BETWEEN 0 and 14 THEN '00'
        WHEN minute(date_action) BETWEEN 15 and 29 THEN '15'
        WHEN minute(date_action) BETWEEN 30 and 44 THEN '30'
        WHEN minute(date_action) BETWEEN 45 and 59 THEN '45'
    END AS intervals
FROM
    clients
WHERE
    HOUR(date_action) = 09
    AND DAY(date_action) = 15
    AND MONTH(date_action) = 07
    AND YEAR(date_action) = 2013
    AND rep_id = 28
GROUP BY intervals

Answer 2

select period, Sum(NumberOfTimes) as NumberOfTimes
From
(Select minute(date_action) % 15 as period, 1 as NumberOfTimes
From Clients
WHERE
    HOUR(date_action) = 09
    AND DAY(date_action) = 15
    AND MONTH(date_action) = 07
    AND YEAR(date_action) = 2013
    AND rep_id = 28
) dummyName
Group By period

将是另一种方式

％是模数运算符

使用MySQL计算每个时间间隔内的记录数

2 个答案: