Question

我有一个名为Dummy的表，如下所示：

No.   Name
1     ABC
2     NMD
2     SDSDS
1     23ererer

现在我希望将所有Name列连接到一个给定的数字

对于前。说号码是1我希望ABC23ererer作为我的输出

这是在ORACLE（SQL）中完成的，不使用PL-SQL。

如何做到这一点？

Answer 1

这可能会有所帮助......

select NO,
  listagg(NAME, ',') within group (order by NAME) as name
from TableName
group by NO

或者检查this

Answer 2

oracle10g不支持LISTAGG。如果您有10g我认为以下查询将帮助您。

select No, rtrim(Name,',') Name
       from ( select No
      , Name, rn
         from yourtable
               model
                      partition by (No)
                        dimension by (row_number() over
                                     (partition by No order by Name) rn
                                    )
                       measures     (cast(Name as varchar2(40)) Name)
                       rules
                       ( Name[any] order by rn desc = Name[cv()]||''||Name[cv()+1]
                       )
              )
        where rn = 1
        order by NO

查看您的demo in sql fiddle

Answer 3

SELECT "No.", LISTAGG(Name, ',') WITHIN GROUP (ORDER BY "No.") AS Name
FROM TableName
GROUP BY "No.";

Answer 4

试试这个：

SELECT Number+' '+
Name FROM table_name

在SQL中连接行

4 个答案: